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问题描述

请问c具有参考?即在C ++:

 无效美孚(INT&安培; I)


解决方案

没有,没有。它的指针的,但他们不完全是一回事。

在特定的,在C所有的参数都是按值传递,而不是传递按引用是可作为C ++。当然,你可以排序模拟的传递由引用通过指针:

 无效美孚(INT * X)
{
    * X = 10;
}...INT Y = 0;
富(安培; Y); //通过值传递的指针
// y值现在是10

有关指针和引用之间差异的更多详细信息,请参阅。 (也请不要问我,因为我不是一个C或C ++程序员:)

Does C have references? i.e. as in C++ :

void foo(int &i)
解决方案

No, it doesn't. It has pointers, but they're not quite the same thing.

In particular, all arguments in C are passed by value, rather than pass-by-reference being available as in C++. Of course, you can sort of simulate pass-by-reference via pointers:

void foo(int *x)
{
    *x = 10;
}

...

int y = 0;
foo(&y); // Pass the pointer by value
// The value of y is now 10

For more details about the differences between pointers and references, see this SO question. (And please don't ask me, as I'm not a C or C++ programmer :)

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10-27 13:22