在jQuery中使用.fadeOut()时禁用点击

问题描述

我正在制作纸牌游戏.当用户单击卡时，卡淡出.但是，此刻存在一个严重的错误.用户可以多次单击一张卡，从而将多个卡号添加到阵列中(实际上是挑选很多卡).

I am building a card game. When the user clicks the card, the card fades out. However, at the moment, there is a serious bug. The user can click one card multiple times, adding multiple card numbers to an array (essentially picking lots of cards).

我该如何解决?到目前为止，这是我的代码:

How can i resolve this? Here is my code so far:

$(clicked_id).fadeOut('fast');

任何帮助将不胜感激！

完整代码:

<script>
var cardsPicked = new Array;

var suits = ["&hearts;", "&diams;", "&clubs;", "&spades;"];
var king = 0;
var numbers = ["A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"];
var cardRules = ["Waterfall", "You", "Me", "Girls", "Thumbmaster", "Guys", "Heaven", "Mate", "Rhyme", "Catagories", "Make a rule", "Question master", "Pour your drink!"];

var currentId;

function getCard(clicked_id) {

    clicked_id = "#" + clicked_id;

    $(clicked_id).fadeOut('fast');

    var newCard = Math.floor((Math.random() * 13) + 1);

    var newSuit = Math.floor((Math.random() * 4) + 1);
    var currentCard;
    var x = document.getElementById("pick");
    var rules = document.getElementById("rules");
    var kings = document.getElementById("kings");
    var currentCards = document.getElementById("currentCard");

    if (cardsPicked.indexOf(numbers[newCard - 1] + " " + suits[newSuit - 1]) == -1) {

        if (numbers[newCard - 1] == "K" && king < 4) {
            king = king + 1;
        }
        if (king == 4) {
            king = "All kings found!";
            alert("Fourth king picked. Down the jug!");
        }
        cardsPicked.push(numbers[newCard - 1] + " " + suits[newSuit - 1]);
        for (count = 0; count < cardsPicked.length; count++)
        currentRule = cardRules[newCard - 1];

        x.innerHTML = cardsPicked;
        currentCards.innerHTML = numbers[newCard - 1] + " " + suits[newSuit - 1];
        rules.innerHTML = currentRule;
        kings.innerHTML = king;

    } else {

        getCard();
    }

}

推荐答案

尝试一下

$(clicked_id).off().fadeOut('fast');

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如果事件是由内联onclick调用的:

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In case the event is called by inline onclick :

$(clicked_id).prop("onclick", "").off().fadeOut('fast');

演示

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