本文介绍了getText()方法必须从UI线程调用(Android的工作室)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图创建一个登录名的应用程序。不过,我有一个问题。

I'm trying to create a login for an application. However I have a problem.

这是我的code:

package com.forgetmenot.loginregister;


import java.util.ArrayList;
import java.util.List;

import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.content.Intent;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class MainActivity extends Activity {
    EditText uname, password;
    Button submit;
    // Creating JSON Parser object
    JSONParser jParser = new JSONParser();
    private static final String TAG = "Login";

    JSONObject json;
    private static String url_login = "http://localhost:8080/ForgetMeNotApplication/Login";
   //JSONArray incoming_msg = null;
   @Override
   protected void onCreate(Bundle savedInstanceState) {
       super.onCreate(savedInstanceState);
       setContentView(R.layout.activity_main);
       findViewsById();
       submit.setOnClickListener(new View.OnClickListener() {

           @Override
           public void onClick(View arg0) {
               // execute method invokes doInBackground() where we open a Http URL connection using the given Servlet URL
               //and get output response from InputStream and return it.
                new Login().execute();

           }
       });
    }
    private void findViewsById() {

        uname = (EditText) findViewById(R.id.txtUser);
        password = (EditText) findViewById(R.id.txtPass);
        submit = (Button) findViewById(R.id.login);
    }
    private class Login extends AsyncTask<String, String, String>{

        @Override
        protected String doInBackground(String... args) {
            // Getting username and password from user input

            String username = uname.getText().toString();
            String pass = password.getText().toString();

            List<NameValuePair> params = new ArrayList<NameValuePair>();
            params.add(new BasicNameValuePair("u",username));
            params.add(new BasicNameValuePair("p",pass));
            json = jParser.makeHttpRequest(url_login, "GET", params);
            String s=null;

            try {
                s= json.getString("info");
                Log.d("Msg", json.getString("info"));
                if(s.equals("success")){
                    Intent login = new Intent(getApplicationContext(), home.class);
                    login.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
                    startActivity(login);
                    finish();
                }
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            return null;
        }

    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.menu_main, menu);
        return true;
    }

    @Override
    public boolean onOptionsItemSelected(MenuItem item) {
        // Handle action bar item clicks here. The action bar will
        // automatically handle clicks on the Home/Up button, so long
        // as you specify a parent activity in AndroidManifest.xml.
        int id = item.getItemId();
        if (id == R.id.action_settings) {
            return true;
        }
        return super.onOptionsItemSelected(item);
    }
}

Android的工作室表示,法的getText()必须调用从UI线程在istructions: uname.getText()的toString() ; password.getText()的toString(); 可能的解决方案?

Android studio says that method getText() must be called from the UI Thread at the istructions: uname.getText().toString(); and password.getText().toString(); Possible solutions??

推荐答案

试试这个:

submit.setOnClickListener(new View.OnClickListener() {

           @Override
           public void onClick(View arg0) {

               String username = uname.getText().toString();
               String pass = password.getText().toString();
               new Login().execute(username, pass);

           }
       });
    }
    private void findViewsById() {

        uname = (EditText) findViewById(R.id.txtUser);
        password = (EditText) findViewById(R.id.txtPass);
        submit = (Button) findViewById(R.id.login);
    }
    private class Login extends AsyncTask<String, String, String>{

        @Override
        protected String doInBackground(String... args) {
            // Getting username and password from user input

            String username = args[0];
            String pass = args[1];

这篇关于getText()方法必须从UI线程调用(Android的工作室)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-20 19:59