什么是boost :: bind的返回类型？

问题描述

我想将一个函数的binder保存到一个变量中，通过利用它的操作符重载设施在下面的代码中重复使用它。这里是实际做我想要的代码：

I want to save the "binder" of a function to a variable, to use it repetitively in the following code by exploiting its operator overloading facilities. Here is the code that actually does what I want:

 
 

std::tr1::function<>
BOOST_AUTO()
c++0x 'auto' keywords (Type Inference)

it's close cousing decltype() can help you move further

 
 
 
 1。
 
 
 



1.


std::tr1::function<int> f; // can be assigned from a function pointer, a bind_expression, a function object etc

int realfunc();
int realfunc2(int a);

f = &realfunc;
int dummy;
f = tr1::bind(&realfunc2, dummy);
 
 
 
 2。
 
 
 
 BOOST_AUTO支持语法c ++ 0x auto没有编译器c ++ 0x支持：
2.
BOOST_AUTO() aims to support the semantics of c++0x auto without compiler c++0x support:
BOOST_AUTO(f,boost::bind(&T::some_complicated_method, _3, _2, "woah", _2));
 
 
 
 3。
 
 
 
与编译器支持：
3.
Essentially the same but with compiler support:
template <class T> struct DoWork { /* ... */ };

auto f = boost::bind(&T::some_complicated_method, _3, _2, "woah", _2));

DoWork<decltype(T)> work_on_it(f); // of course, using a factory would be _fine_
注意，auto可能是为这种类型发明的的情况：实际类型是你不想知道，并且可能因编译器/平台/库而异
Note that auto has probably been invented for this kind of situation: the actual type is a 'you don't want to know' and may vary across compilers/platforms/libraries
                        
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