问题描述
我有一个一维 numpy 数组，我需要确定任何值是零还是非常接近。
通过这一行，我可以快速检查零：
I have a one dimensional numpy array for which I need to find out if any value is zero or very close to it.With this line I can check for zeros rapidly:
if 0. in my_array:
# do something
，但是我也有一些很小的元素，例如1.e-22，我也想处理设为零（否则我会得到进一步的被零除警告）
but I also have very small elements like 1.e-22 which I would also like to treat as zeros (otherwise I get a Divide by zero warning further down the road)
说我的阈值为1.e-6，我想有效检查我数组中的 any 值是否小于该值。我该怎么做呢？
Say my threshold is 1.e-6 and I want to efficiently check if any value in my array is smaller than that. How can I do this?
推荐答案
没有理由在Python中循环；因为没有理由在Python中循环。只是播放Abs和<并使用：
There's no reason to loop in Python; just broadcast the abs and the < and use np.any:
np.any(np.absolute(my_array) < eps)
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