问题描述
我有一个函数，该函数需要一个指向char **的指针，并用字符串(我猜是字符串数组)填充它. * list_of_strings *是在函数内部分配的内存.
I have a function that takes a pointer to a char ** and fills it with strings (an array of strings I guess). *list_of_strings* is allocated memory inside the function.
char * *list_of_strings = NULL;
/* list_of_strings malloc'd inside function */
fill_strings_with_stuff(&list_of strings);
use_list_for_something(list_of_strings);
/* Now how do I free it all? */
使用字符串后如何释放内存?如果我打电话
How would I go about freeing the memory after I've used the strings? If I call
free(list_of_strings);
那不只是释放实际的指针，而不是释放每个字符串本身正在使用的内存吗?如何完全释放内存
won't that just free the actual pointers and not the memory each string itself was using? How do I completely free the memory
为清楚起见，该函数看起来像这样:
Just for clarity the function looks something like this:
fill_strings_with_stuff(char *** list)
{
*list = malloc(AMOUNT);
for (i = 0; i < SOMETHING; i++) {
*(list + i) = malloc(LINE_LEN);
*(list + i) = some_string_from_somewhere
}
/* ... */
}
推荐答案
是的.
通过遍历数组并在 释放数组本身之前一一释放每个字符串.例如
By looping through the array and freeing each string one by one before freeing up the array itself. E.g.
for (i = 0; i < SOMETHING; i++) {
free(list[i]);
}
free(list);
这篇关于释放已分配给char指针(字符串)数组的内存.我必须释放每个字符串还是仅释放"main"字符串?指针?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！