本文介绍了请检查以下语法并更正它有4个错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
main()
{
char *name;
int length;
char *cptr = name;
name = "DELHI";
printf {"%s\n", name};
while{*cptr != '\0'}
{
printf{"%C is stored at address %u\n", *cptr, cptr};
cptr++;
}
length = cptr - name;
printf{"\nLength of the string = %d\n", length};
}
推荐答案
#include <stdio.h>
int main()
{
char *name;
name = "DELHI";
int length;
char *cptr = name;
printf ("%s\n", name);
while(*cptr != '\0')
{
printf("%C is stored at address %p\n", *cptr, cptr);
cptr++;
}
length = cptr - name;
printf("\nLength of the string = %d\n", length);
return 0;
}
顺便说一句,你真的很喜欢花括号,不是吗?
By the way, you really like curly braces, don't you?
这篇关于请检查以下语法并更正它有4个错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!