本文介绍了在OutOfMemory时生成java转储的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个程序最终应该生成 OutOfMemory
。
程序代码是:
I have a program that should eventually generate OutOfMemory
.The program code is:
public class VeryLargeObject implements Serializable {
public static final int SIZE = 1 << 12;
public String tag;
public int[][] bigOne = new int[SIZE][SIZE];
{
// Initialize bigOne
for(int i = 0; i < SIZE ; ++i) {
for(int j = 0; j < SIZE; ++j) {
bigOne[i][j] = (int) (Math.random() * 100);
}
}
}
public VeryLargeObject(String tag) {
this.tag = tag;
}
public static void main(String args[]) {
VeryLargeObject[] vla = new VeryLargeObject[1 << 12];
for(int i = 0; i < Integer.MAX_VALUE; ++i) {
vla[i] = new VeryLargeObject("aa");
}
}
}
我运行程序以下参数:
java VeryLargeObject -Xms1024m -Xmx1024m -XX:+HeapDumpOnOutOfMemoryError -XX:HeapDumpPath="D:\workspace"
程序因OutOfMemory失败,但没有生成转储文件。你知道为什么吗?
Exception in thread "main" java.lang.OutOfMemoryError: Java heap space
at VeryLargeObject.<init>(VeryLargeObject.java:14)
at VeryLargeObject.main(VeryLargeObject.java:32)
推荐答案
首先删除XX选项和任何选项 BEFORE VeryLargeObject
,否则你将参数传递给java程序而不是JVM
For starter drop the XX options and any options BEFORE VeryLargeObject
, otherwise you pass the parameters to the java program and not the JVM
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