问题描述
我需要调用我的过程,然后忘记它.我有一种方法,该方法能够调用我的过程并返回已接受"消息.不用等待.问题是我无法在新线程内(内部操作)访问HttpContext.我想将HttpContext从主线程转发到新线程,但是它不起作用.
I need to invoke my process and forget about it. I have a method which is able to invoke my process and return "Accepted" without waiting. The problem is that I cannot access HttpContext inside the new thread (inside action). I would like to forward HttpContext from the main thread to the new one however it doesn't work.
private async Task<string> InvokeAsyncProcess(bool wait, Func<Task<Statistics>> action, string name)
{
var oldHttpContext = System.Web.HttpContext.Current;
if (wait)
{
Statistics stats = await action.Invoke();
return JsonConvert.SerializeObject(stats);
}
else
{
Thread job = new Thread(async f =>
{
try
{
System.Web.HttpContext.Current = oldHttpContext;
await LogService.LogAsync(LogCategory.Info, name, "Started in the background", null, null);
Statistics stats = await action.Invoke();
await LogService.LogAsync(LogCategory.Info, name, string.Format("Finished, returned data: {0}", JsonConvert.SerializeObject(stats)), null, null);
}
catch (Exception e)
{
await LogService.LogAsync(LogCategory.Error, name, "Error...", e, null);
}
});
job.Start();
Response.StatusCode = (int)HttpStatusCode.Accepted;
return "Accepted"; // Accepted = 202
}
}
推荐答案
您可以使用 ParameterizedThreadStart
You can pass parameters to a new thread with ParameterizedThreadStart
var job = new Thread(async input =>
{
HttpContext httpContext = (HttpContext)input;
});
job.Start(HttpContext.Current)
尽管我不建议将 HttpContext
传递给新线程.这是一个好主意,因为 HttpContext
不是线程安全的.同样,在您返回"Accepted";
之后,当前请求将完成,并且将处置 HttpContext
.因此,您可能会在新线程中获得一些已处置的对象.
Although I don't recommend passing HttpContext
to a new thread. It's a good idea since HttpContext
is not thread safe. Also after you return "Accepted";
the current request will finish and it will dispose HttpContext
. So you might get some disposed objects in the new thread.
这篇关于如何将HttpContext传递给新线程C#的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!