如何使用Codeigniter计算每列的总和

问题描述

控制器

这是控制器页面。

 code> public function index（）{
 $ data = array（
'year'=> $ this-> year_model-> list_all（），
'speces' => $ this-> speces_model-> list_all（），
）; 
 foreach（$ data ['year'] as $ value）：
 
 $ temp = array（）; 
 $ temp ['year_key'] = $ value ['year-range']; 
 $ temp ['year_id'] = $ value ['id']; 
 
 
 $ temp ['speces_key'] = array（）; 
 foreach（$ data ['speces'] as $ value1）：
 
 $ temp ['speces_key'] [$ value1 ['name']] = $ this-& > get_where（'spendingituredata'，array（'spacesId'=> $ value1 ['id']，'yearId'=> $ value ['id']）） - > row_array（）; 
 
 endforeach; 
 $ final_result [] = $ temp; 
 
 endforeach; 
 $ data ['result'] = $ final_result; 
 $ this-> load-> view（'site / template'，$ data）; 
} 
  

查看

这是查看文件。

 < table& 
< thead> 
< tr> 
< th>年范围< / th> 
<？php foreach（$ speces as $ value）：？> 
< th> <？php echo $ value ['name']; ？>< / th> 
<？php endforeach; ？> 
< th> TOTAL< / th> 
< / tr> 
< / thead> 
< tbody> 
<？php foreach（$ result as $ value）：？> 
<？php $ sum = 0; ？> 
< tr> 
 td><？php echo $ value ['year_key']; ？>< / td> 
 
<？php foreach（$ value ['speces_key'] as $ key => $ value2）：？> 
< td><？php echo $ value2 ['data']; ？>< / td> 
<？php $ sum + = $ value2 ['data']; ？> 
<？php endforeach; ？> 
< td><？php echo $ sum; ？>< / td> 
< / tr> 
<？php endforeach; ？> 
< tr> 
< td>总计< / td> 
< / tr> 
< / table> 
  

我的问题：如何计算以上屏幕截图中的总计。

所以请查看上面的截图和Calculatre总计为所有动物根据年。

解决方案

尝试使用这样：

  $ select = array（
'table.col1'，
'table.col2'，
'table.COW + table.DOG + table.CAT + table.BIRD + table.ARV + table.CAMP as TOTAL'
）; 
 $ this-> db-> select（$ select）; 
 $ this-> db-> from（'spendingituredata'）; 
 $ this-> db->其中（array（'spacesId'=> $ value1 ['id']，'yearId'=> $ value ['id' 
 $ this-> db-> row_array（）; 
  

或使用这个简单的SQL查询

从表格中选择COW + DOG + CAT + BIRD + ARV + CAMP作为TOTAL，其中col ='val';

Controller

This is Controller Page.

public function index() {
$data = array(
     'year' => $this->year_model->list_all(),
     'speces' => $this->speces_model->list_all(),
       );
          foreach ($data['year'] as $value):

                $temp = array();
                $temp['year_key'] = $value['year-range'];
                $temp['year_id'] = $value['id'];


                $temp['speces_key'] = array();
                foreach ($data['speces'] as $value1):

                    $temp['speces_key'][$value1['name']] = $this->db->get_where('expendituredata', array('spacesId' => $value1['id'], 'yearId' => $value['id']))->row_array();

                endforeach;
                $final_result[] = $temp;

            endforeach;
            $data['result'] = $final_result;
            $this->load->view('site/template', $data);
        }

View

This is View file.

 <table>
 <thead>
      <tr>
        <th>Year Range</th>
        <?php foreach ($speces as $value): ?>
         <th> <?php echo $value['name']; ?></th>
          <?php endforeach; ?>
          <th>TOTAL</th>
           </tr>
  </thead>
   <tbody>
       <?php foreach ($result as $value): ?>
          <?php $sum = 0; ?>
           <tr>
              td><?php echo $value['year_key']; ?></td>

                <?php foreach ($value['speces_key'] as $key => $value2): ?>
                  <td><?php echo $value2['data']; ?></td>
                    <?php $sum+= $value2['data']; ?>
                  <?php endforeach; ?>
                <td><?php echo $sum; ?></td>
                </tr>
     <?php endforeach; ?>
                <tr>
                    <td>Total</td>
                </tr>
</table>

ScreenShot

MY Question : How to Calculate Total in above screen shot.

so please view above screenshot and Calculatre total for all animal according to year.

解决方案

Try to use something like this :

$select =  array(
                'table.col1',
                'table.col2',
                'table.COW+table.DOG+table.CAT+table.BIRD+table.ARV+table.CAMP as TOTAL'
               );
$this->db->select($select);
$this->db->from('expendituredata');
$this->db->where(array('spacesId' => $value1['id'], 'yearId' => $value['id']));
$this->db->row_array();

Or use this simple SQL query

select COW+DOG+CAT+BIRD+ARV+CAMP as TOTAL from table where col = 'val';

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