问题描述
如何在下面的示例中找到带有正则表达式的字符串，以dd300开头并以逗号结尾（结果包含逗号）？
示例字符串：
dd301 / 122/4454，dd300 / 122/300，NR45，
预期成果：
dd300 / 122/300，
我的尝试：
可以获得以下匹配dd300，但需要知道如何包含正斜杠并停在逗号处。
（？<！\w）dd300
How do I find the string with a Regular Expression in the example below that start with 'dd300' and end with a comma (result to include the comma)?
Example string:
dd301/122/4454,dd300/122/300,NR45,
Expected Result:
dd300/122/300,
What I have tried:
Can get the following to match dd300, but need to know how to include forward slashes and stop at the comma.
(?<!\w)dd300
推荐答案
(dd300\/.+?,)括号只是当你需要访问匹配的字符串时需要。
根据你的输入，你也可以使用更具体的正则表达式。例如，如果 dd300 总是以两个斜线分隔的数字表示，则可以是
The parentheses are only necessary when you need to access the matched string.
Depending on your input you may also use a more specific regex. If for example the dd300 is always follwed by two slash separated numbers it can be
(dd300\/\d+\/\d+,)其中 \d 指定与使用相同的任何数字[0-9] 。
dd300.*?,哪个是''dd300';后跟任何字符，任意数量的重复，尽可能少;然后是逗号。
如果你要去使用正则表达式，然后获取的副本[] - 它是免费的，它会检查并生成正则表达式。
Which is "'dd300'; followed by any character, any number of repetitions, as few as possible; then a comma".
If you are going to work with regexes, then get a copy of Expresso[^] - it's free, and it examines and generates Regular expressions.
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