本文介绍了解释一下用JAVA编写的这一行的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
在HACKERRANK中，这行代码非常频繁地出现.我认为这是为了跳过空格，但是"\r\u2028\u2029\u0085"的意思是什么
In HACKERRANK this line of code occurs very frequently. I think this is to skip whitespaces but what does that "\r\u2028\u2029\u0085" thing mean
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
推荐答案
Scanner.skip跳过与模式匹配的输入，这里的模式是:-
- ?完全匹配零或前一个字符.
- |替代
- []匹配 中出现的单个字符
- \ r匹配回车符
-
\ n换行符
- ? matches exactly zero or one of the previous character.
- | Alternative
- [] Matches single character present in
- \r matches a carriage return
\n newline
\ u2028将字符与区分大小写的索引2018 base 16(8232 base 10或20050 base 8)匹配
\u2028 matches the character with index 2018 base 16(8232 base 10 or 20050 base 8) case sensitive
- \ r与回车符(ASCII 13)匹配
- \ n与换行符(ASCII 10)匹配
- 匹配[\ n \ r \ u2028 \ u2029 \ u0085]下面列表中存在的单个字符
- \ n与换行符(ASCII 10)匹配
- \ r与回车符(ASCII 13)匹配
- \ u2028从字面上(区分大小写)LINE SEPARATOR匹配具有索引202816(823210或200508)的字符
- \ u2029从字面上将字符与索引202916(823310或200518)相匹配(区分大小写)PARAGRAPH SEPARATOR
- \ u0085从字面上(区分大小写)将索引为8516(13310或2058)的字符与下一行匹配
- Match a single character present in the list below [\n\r\u2028\u2029\u0085]
- \n matches a line-feed (newline) character (ASCII 10)
- \r matches a carriage return (ASCII 13)
- \u2028 matches the character with index 202816 (823210 or 200508) literally (case sensitive) LINE SEPARATOR
- \u2029 matches the character with index 202916 (823310 or 200518) literally (case sensitive) PARAGRAPH SEPARATOR
- \u0085 matches the character with index 8516 (13310 or 2058) literally (case sensitive) NEXT LINE
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