获取ArrayIndexOutOfBoundsException异常 | ArrayIndexOutOfBoundsException

本文介绍了获取ArrayIndexOutOfBoundsException异常的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

过去几天获得 ArrayIndexOutOfBoundsException .我知道#SO上已经问过这类问题.我尝试过.

Past few days Getting ArrayIndexOutOfBoundsException .I know this type of questions already asked on #SO . I tried .

代码

String[] Child_DOB = "KUSHAGRA (SON)-07/05/94AANVI (DAUGHTER)-12/06/00 VARENYA (SON) - 26/12/05";
        ArrayList<String> children_List = new ArrayList<String>();
        ArrayList<Integer> Length_List = new ArrayList<Integer>();
        String Children_Details_str = "";

        int i = 0;
        while (i < Child_DOB.length) {
            String name_dob = Child_DOB[i] + "  " + Child_DOB[i + 1];//this line
            if (i > 3)
                Children_Details_str = Children_Details_str + "\n" + name_dob;
            else
                Children_Details_str = Children_Details_str + name_dob + "  ";
            children_List.add(name_dob);
            Length_List.add(Child_DOB[i].length());
            Length_List.add(Child_DOB[i + 1].length());
            i = i + 2;
        }

我可以知道实现目标的正确方法是什么?任何帮助将不胜感激

May I know what is the correct way to achieve my objective? Any help would be greatly appreciated

推荐答案

将while循环condition更改为:

 while (i < Child_DOB.length - 1)

说明:

例如，在您的代码中，Child_DOB.length是5，i值是4，

For example, Child_DOB.length is 5 and i value is 4, In your code:

    int i = 4;
    while (i < 5) {
        String name_dob = Child_DOB[4] + "  " + Child_DOB[4 + 1];

此处Child_DOB[5]导致ArrayIndexOutOfBoundsException，因为数组index从0开始并且您的Child_DOB索引为[0 1 2 3 4].

Here Child_DOB[5] causes ArrayIndexOutOfBoundsException because array index start from 0 and your Child_DOB index's are [0 1 2 3 4].

希望这会有所帮助〜

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