如何使“剪切”命令把几个连续的分隔符视为一个？

问题描述

我试图从基于列的，space'调整文本流中提取一定的（第四）字段。我试图使用剪切按以下方式命令：

I'm trying to extract a certain (the fourth) field from the column-based, 'space'-adjusted text stream. I'm trying to use the cut command in the following manner:

猫的text.txt |切-d-f 4

不幸的是，剪切不把多个空格为一个分隔符。我可以通过awk的管道已

Unfortunately, cut doesn't treat several spaces as one delimiter. I could have piped through awk

的awk'{printf的$ 4; }

或sed的

的sed -ES / [[：空间：]] + / / G

崩溃的空间，但我想知道是否有任何的方式来处理剪切和几个分隔符本身？

to collapse the spaces, but I'd like to know if there any way to deal with cut and several delimiters natively?

推荐答案

尝试：

cat text.txt | tr -s ' ' | cut -d ' ' -f 4

在 TR 手册页：

-s, --squeeze-repeats   replace each input sequence of a repeated character
                        that is listed in SET1 with a single occurrence
                        of that character

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