本文介绍了如何使用DateTime键(Swift 4)对NSDictionary数组进行排序?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个NSDictionary的NSArray
I have an NSArray of NSDictionary
let Array = (
{ name = "Auni";
age = "24";
transactionTime = "01-02-2011 12:32:39" },
{ name = "Atiqah";
age = "23";
transactionTime = "02-02-2013 10:32:41" },
{ name = "Aida";
age = "22";
transactionTime = "04-02-2020 18:32:21"})
如何按最近的transactionTime排序此数组?使用Swift4.
How do I sort this array by most recent transactionTime? Using Swift4.
谢谢.
让后端人员为您完成这项工作更容易.
It's easier to have back-end people do it for you.
推荐答案
您不需要转换为Date
对象,dateStrings直接比较也将起作用.
You do not need to convert into Date
object, dateStrings direct comparison will also work.
array.sort { (dict1, dict2) -> Bool in
/// Considering "transactionTime" key always exists.
let transactionTime1 = dict1["transactionTime"]!
let transactionTime2 = dict2["transactionTime"]!
/// Sort in descending order
return transactionTime1 > transactionTime2
}
如果需要对日期对象进行一些计算,则还可以在运行时将字符串转换为日期对象,如下例所示:
In case you need some calculation on date objects then You can also convert the string into date objects at run time like below example:
let df = DateFormatter()
df.dateFormat = "dd-MM-yyyy HH:mm:ss"
array.sort { (dict1, dict2) -> Bool in
/// Considering "transactionTime" key always exists.
let transactionTime1 = dict1["transactionTime"]!
let transactionTime2 = dict2["transactionTime"]!
let date1 = df.date(from: transactionTime1)!
let date2 = df.date(from: transactionTime2)!
/// Sort in descending order
return date1 > date2
}
print(array)
输出
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