问题描述
尝试在Java中将字节转换为String时遇到问题，代码如下：
byte [] bytes = {1,2，-3};
byte [] transferred = new String（bytes，Charsets.UTF_8）.getBytes（Charsets.UTF_8）;
且原始字节与传输的字节不同，分别为
[1,2，-3]
[1,2，-17，-65，-67]
我曾经认为这是由于负数-3的UTF-8字符集映射。所以我把它改成-32。但转移的阵列保持不变！
[1,2，-32]
[1,2， - 17，-65，-67]
所以我非常想知道当我打电话给新的时候会发生什么字符串（字节）：）
并非所有字节序列在UTF-8中都有效。
中）是非法的，但你的字节数组没有这样的顺序。
您的UTF-8无效。 Java UTF-8解码器使用Unicode代码点替换此无效字节 -3 （另见）。在UTF-8中，代码点U + FFFD是十六进制 0xEF 0xBF 0xBD （二进制 11101111 10111111 10111101 ），用Java表示as -17，-65，-67 。
I have a problem when trying to convert bytes to String in Java, with code like:
byte[] bytes = {1, 2, -3};
byte[] transferred = new String(bytes, Charsets.UTF_8).getBytes(Charsets.UTF_8);
and the original bytes are not the same as the transferred bytes, which are respectively
[1, 2, -3]
[1, 2, -17, -65, -67]
I once thought it is due to the UTF-8 charset mapping for the negative "-3". So I change it to "-32". But the transferred array remains the same!
[1, 2, -32]
[1, 2, -17, -65, -67]
So I strongly want to know exactly what happens when I call new String(bytes) :)
Not all sequences of bytes are valid in UTF-8.
UTF-8 is a smart scheme with a variable number of bytes per code point, the form of every byte indicating how many other bytes follow for the same code point.
Refer to this table:
Now let's see how it applies to your {1, 2, -3}:
Bytes 1 (hex 0x01, binary 00000001) and 2 (hex 0x02, binary 00000010) stand alone, no problem.
Byte -3 (hex 0xFD, binary 11111101) is the start byte of a 6-byte sequence (which is actually illegal in the current UTF-8 standard), but your byte array does not have such a sequence.
Your UTF-8 is invalid. The Java UTF-8 decoder replaces this invalid byte -3 with Unicode codepoint U+FFFD REPLACEMENT CHARACTER (also see this). in UTF-8, codepoint U+FFFD is hex 0xEF 0xBF 0xBD (binary 11101111 10111111 10111101), represented in Java as -17, -65, -67.
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