本文介绍了如何比较结构,切片,地图是否相等?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想检查两个结构是否相等,但有一些问题:
I want to check that two structs are equal, but have some problem:
package main
import (
"fmt"
"reflect"
)
type T struct {
X int
Y string
Z []int
M map[string]int
}
func main() {
t1 := T{
X:1,
Y:"lei",
Z:[]int{1,2,3},
M:map[string]int{
"a":1,
"b":2,
},
}
t2 := T{
X:1,
Y:"lei",
Z:[]int{1,2,3},
M:map[string]int{
"a":1,
"b":2,
},
}
fmt.Println(t2 == t1)
//error - invalid operation: t2 == t1 (struct containing []int cannot be compared)
fmt.Println(reflect.ValueOf(t2) == reflect.ValueOf(t1))
//false
fmt.Println(reflect.TypeOf(t2) == reflect.TypeOf(t1))
//true
//Update: slice or map
a1 := []int{1,2,3,4}
a2 := []int{1,2,3,4}
fmt.Println(a1==a2)
//invalid operation: a1 == a2 (slice can only be compared to nil)
m1 := map[string]int{
"a":1,
"b":2,
}
m2 := map[string]int{
"a":1,
"b":2,
}
fmt.Println(m1==m2)
// m1 == m2 (map can only be compared to nil)
}
推荐答案
您可以使用,或者您可以实施自己的功能(哪种性能明智的会比使用反射更好):
You can use reflect.DeepEqual, or you can implement your own function (which performance wise would be better than using reflection):
m1 := map[string]int{
"a":1,
"b":2,
}
m2 := map[string]int{
"a":1,
"b":2,
}
fmt.Println(reflect.DeepEqual(m1, m2))
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