成员运算符“=="必须至少有一个类型参数

问题描述

我正在尝试在qualityClass中实现Equatable协议，但显示成员运算符'=='必须至少有一个'eqaualityClass'类型的参数.有人能解释一下这里出了什么问题吗?

I am trying to implement Equatable protocol in equalityClass, but showing Member operator '==' must have at least one argument of type 'eqaualityClass' .can any one explain whats going wrong here?

protocol Rectangle: Equatable {

    var width: Double { get }
    var height: Double { get }

}

class eqaualityClass:Rectangle{

    internal var width: Double = 0.0
    internal var height: Double = 0.0

      static func == <T:Rectangle>(lhs: T, rhs: T) -> Bool {
          return lhs.width == rhs.width && rhs.height == lhs.height
     }
}

推荐答案

你需要让你的 Rectangle 协议成为一个类.试试这个:

You need to make your Rectangle protocol a class. Try like this:

protocol Rectangle: class, Equatable {
    var width: Double { get }
    var height: Double { get }
}

class Equality: Rectangle {
    internal var width: Double = 0
    internal var height: Double = 0
    static func ==(lhs: Equality, rhs: Equality) -> Bool {
        return lhs.width == rhs.width && rhs.height == lhs.height
    }
}

或者简单地说:

protocol Rectangle: Equatable {
    var width: Double { get }
    var height: Double { get }
}

extension Rectangle {
    static func ==(lhs: Self, rhs: Self) -> Bool {
        return lhs.width == rhs.width && rhs.height == lhs.height
    }
}

class Equality: Rectangle {
    internal var width: Double = 0
    internal var height: Double = 0
}

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