确定Python类是Abstract基类还是Concrete类

问题描述

我的Python应用程序包含许多抽象类和实现。例如：

My Python application contains many abstract classes and implementations. For example:

import abc
import datetime

class MessageDisplay(object):
    __metaclass__ = abc.ABCMeta

    @abc.abstractproperty
    def display(self, message):
        pass

class FriendlyMessageDisplay(MessageDisplay):
    def greet(self):
        hour = datetime.datetime.now().timetuple().tm_hour

        if hour < 7:
            raise Exception("Cannot greet while asleep.")
        elif hour < 12:
            self.display("Good morning!")
        elif hour < 18:
            self.display("Good afternoon!")
        elif hour < 20:
            self.display("Good evening!")
        else:
            self.display("Good night.")

class FriendlyMessagePrinter(FriendlyMessageDisplay):
    def display(self, message):
        print(message)

FriendlyMessagePrinter 是我们可以使用的具体类...

FriendlyMessagePrinter is a concrete class that we can use...

FriendlyMessagePrinter().greet()

Good night.

...但是 MessageDisplay 和 FriendlyMessageDisplay 是抽象类，尝试实例化一个类会导致错误：

...but MessageDisplay and FriendlyMessageDisplay are abstract classes and attempting to instantiate one would result in an error:

TypeError: Can't instantiate abstract class MessageDisplay with abstract methods say

如何我可以检查给定的类对象是否是（不可实例化的）抽象类？

How can I check if a given class object is an (uninstantiatable) abstract class?

推荐答案

import inspect
print(inspect.isabstract(object))                  # False
print(inspect.isabstract(MessageDisplay))          # True
print(inspect.isabstract(FriendlyMessageDisplay))  # True
print(inspect.isabstract(FriendlyMessagePrinter))  # False

这将检查内部标志 TPFLAGS_IS_ABSTRACT 是在类对象中设置的，因此无法像您的实现那样容易地对其进行欺骗：

This checks that the internal flag TPFLAGS_IS_ABSTRACT is set in the class object, so it can't be fooled as easily as your implementation:

class Fake:
    __abstractmethods__ = 'bluh'

print(is_abstract(Fake), inspect.isabstract(Fake)) # True, False

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