进行 Docker Inspect 时如何获取 ENV 变量

问题描述

我想知道如何从 docker inspect 获取环境变量.

I wonder how I get an Environment variable from docker inspect.

当我跑步时

docker inspect -f "{{.Config.Env.PATH}} " 1e2b8689cf06

我得到以下

FATA[0000] template: :1:9: executing "" at <.Config.Env.PATH>: can't evaluate field PATH in type interface {}

推荐答案

用类似的命令直接获取

docker inspect --format '{{ index (index .Config.Env) 1 }}' 797

为我展示

PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin

您会注意到将 1 替换为 0 就像

You will notice that replacing the 1 by 0 like

docker inspect --format '{{ index (index .Config.Env) 0 }}' 797

给予

DISPLAY=:0

事实上，我已经注意到以下各种 docker inspect 从更一般到更精确的显示

In fact I had noticed the following for various docker inspect from a more general to a more precise display

docker inspect --format '{{ (.NetworkSettings.Ports) }}' 87c
map[8000/tcp:[map[HostIp:0.0.0.0 HostPort:49153]]]
docker inspect --format '{{ ((index .NetworkSettings.Ports "8000/tcp") 0) }}' 87c
[map[HostIp:0.0.0.0 HostPort:49153]]
docker inspect --format '{{ index (index .NetworkSettings.Ports "8000/tcp") 0 }}' 87c
map[HostIp:0.0.0.0 HostPort:49153]
docker inspect --format '{{ (index (index .NetworkSettings.Ports "8000/tcp") 0).HostIp }}' 87c
0.0.0.0
docker inspect --format '{{ (index (index .NetworkSettings.Ports "8000/tcp") 0).HostPort }}' 87c
49153

注意:docker inspect -f 有效并且更短，当然，我发布了旧"语法.

Note: docker inspect -f works and is shorter, of course, I posted the "old" syntax.

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