本文介绍了MySQL SELECT SUM 基于另一个表(另一种情况)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
继续我之前的最后一个问题.但现在我在下面添加了一些条件:
Continue my last question before. But now I add some condition below:
根据工作查询代码:
SELECT
R.budgetid_fk,
SUM(R.quantity),
SUM(R.quantity * I.price * COALESCE(CC.amount,1)) as total,
B.budgetid,
B.budget_month
FROM tb_pro_request R
INNER JOIN tb_items I
ON R.itemid_fk = I.itemid
INNER JOIN tb_budgets B
ON R.budgetid_fk = B.budgetid
AND B.active = 'Y'
LEFT JOIN tb_currency_converters CC
ON CC.from_currencyid_fk = I.currencyid_fk
AND CC.to_currencyid_fk = B.currencyid_fk
WHERE
R.investmentid_fk = ''
AND (
R.approval_status = 'P'
OR R.approval_status = 'A'
)
AND DATE_FORMAT(B.budget_month,'%Y-%m') = '2018-03'
AND B.departmentid_fk = 'DP0002'
GROUP BY R.budgetid_fk;
在该代码上,它将从某个列中获取价格的总和.
On that code, It will get the total SUM of price from some column.
requestid | budgetid_fk | category | itemid_fk | quantity | currencyid_fk | price | discount | userid_fk
RQ201803000001 | BU201803000002 | Item | IT0001 | | |
RQ201803000002 | BU201803000002 | Project | | 20 | CU0002 | 750 | 10 | US0004
现在我需要添加额外的代码来计算类别项目(RQ201803000002)
Now I need to add extra code to calculate Category Project(RQ201803000002)
价格与
SUM(R.quantity * I.price * COALESCE(CC.amount,1)) as total
逻辑:
(quantity * (price * currency)) - discount as total2
*need to convert the currency first
*get department from userid_fk
然后积累起来
total + total2
您可以在此处
推荐答案
我想你只是想要这个(如果 discount
来自另一个表格?):
I think you just want this (apart if the discount
come form another table ?):
SUM(R.quantity * (I.price - discount) * COALESCE(CC.amount,1)) as total
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