用双间接打交道时避免不兼容的指针警告

问题描述

假设此程序：

#include <stdio.h>
#include <string.h>

static void ring_pool_alloc(void **p, size_t n) {
    static unsigned char pool[256], i = 0;
    *p = &pool[i];
    i += n;
}

int main(void) {
    char *str;
    ring_pool_alloc(&str, 7);
    strcpy(str, "foobar");
    printf("%s\n", str);
    return 0;
}

...是否有可能以某种方式避免了海湾合作委员会警告

... is it possible to somehow avoid the GCC warning

test.c:12: warning: passing argument 1 of ‘ring_pool_alloc’ from incompatible pointer type
test.c:4: note: expected ‘void **’ but argument is of type ‘char **’

...没有铸造（无效**）（或者干脆禁用兼容性检查）？因为我非常希望保持对间接级别兼容性警告...

... without casting to (void**) (or simply disabling the compatibility checks)? Because I would very much like to keep compatibility warnings regarding indirection-level...

推荐答案

你为什么不改变方法签名，使得它的返回的新指针，而不是通过指针传递呢？事实上，就像普通的的malloc 所做的：

Why don’t you change the method signature such that it returns the new pointer instead of passing it by pointer? In fact, just like regular malloc does:

static void * ring_pool_alloc(size_t n) {
    static unsigned char pool[256], i = 0;
    void *p = &pool[i];
    i += n;
    return p;
}

int main(void) {
    char *str = ring_pool_alloc(7);
    strcpy(str, "foobar");
    printf("%s\n", str);
    return 0;
}

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