本文介绍了使用Netezza以秒为单位的时差?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想在秒钟内在Netezza中获得以分钟为单位的时差.
I want to Get time difference in minutes in Netezza in Seconds.
我有2列:Start(2014-06-01 07:45:04)
和finish(2014-06-01 07:46:58)
事件
我尝试使用DATEDIFF(SECOND,start,finish)
,但是Netezza出现错误.
I have tried Using DATEDIFF(SECOND,start,finish)
, but Netezza shoots an error.
我缺少一个功能吗?
Select R.*,S.*,CM.URL,DATEDIFF(SECOND,R.EVENT_DTM,S.MIN) From CTE_1 R
JOIN CTE_2 S
on S.VISIT_KEY = R.VISIT_KEY
JOIN ADMIN.VW_DIM_CME_METADATA CM on CM.CONTENT_METADATA_KEY = R.CONTENT_METADATA_KEY
推荐答案
在IBM论坛上进行了一些搜索,发现这可行.如果有人提供更好的方法,请发布.谢谢
Did some Searching on the IBM forums and found this which works. If someone comes with better way please do post it. Thanks
Select
R.*,S.*,CM.URL,
EXTRACT(EPOCH from S.MIN - R.EVENT_DTM)DIFF
From CTE_1 R
JOIN CTE_2 S
on S.VISIT_KEY = R.VISIT_KEY
JOIN ADMIN.VW_DIM_CME_METADATA CM on CM.CONTENT_METADATA_KEY = R.CONTENT_METADATA_KEY
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