不能使用getRef()吗?

问题描述

任何人都可以解释为什么这是在说我不能使用getRef来获取被点击的位置吗?从我查看过的所有内容来看，这应该有效，并且出于某种原因，它不起作用.

Can anyone explain why this is saying I can not use getRef to get the position that is being clicked? From everything I have looked up, this should work and for some reason it is not.

public class DeleteChoiceListFragment extends Fragment {

DatabaseReference mRootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference mRestReference = mRootRef.child("restaurants");

List<String> listofrest = new ArrayList<String>();
ListView restaurantListView;
ListAdapter restaurantListAdapter;


public DeleteChoiceListFragment() {
}

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.restaurant_selection_list_frag, container, false);
    restaurantListView = (ListView) view.findViewById(R.id.restaurantListView);

    restaurantListAdapter = new FirebaseListAdapter<Restaurants>(getActivity(), Restaurants.class, R.layout.individual_restaurant_name_nocheckbox, mRestReference) {
        @Override
        protected void populateView(View v, Restaurants model, final int position) {
            TextView restName = (TextView) v.findViewById(R.id.restname);
            restName.setText(model.getName());

            listofrest.add(position, model.getName());
        }
    };

    restaurantListView.setAdapter(restaurantListAdapter);
    restaurantListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {

            Firebase itemtoremove = restaurantListAdapter.getRef(i);
            //I get an error here saying I can't use .getRef()
            itemtoremove.removeValue();


        }
    });
    return view;

  }
 }

推荐答案

您已声明 restaurantListAdapter作为 ListAdapter .即使将 FirebaseListAdapter 对象放入该字段中，您也只能访问在 ListAdapter 上定义的方法.

You've declared restaurantListAdapter as a ListAdapter. Even when you put a FirebaseListAdapter object into that field, you can only access method that are defined on ListAdapter.

解决方案是还声明该字段作为 FirebaseListAdapter :

The solution is to also declare the field as a FirebaseListAdapter:

FirebaseListAdapter restaurantListAdapter;

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