如何减去数组的值但仍在位置

问题描述

如果该值大于特定数据，如何减去该值？

How can I subtract the value of an array if that value is greater than specific data?

例如：

我有一个数组菜单位置的位置 [0,3,10,5,6,9,2,7,1,4,8,11] 我想减去所有较大的值比 selectedDeletedNumbers 保持位置。

I have an array of menu's position [0,3,10,5,6,9,2,7,1,4,8,11] I want to subtract all values that are greater than selectedDeletedNumbers and stay in their position.

示例：如果我删除了 3 和 5 。 我正在使用复选框删除

Example: If I delete 3 and 5. I am using checkbox to delete

输出应该是这样的。

[ 0,8,4,7,2,5,1,3,6,9]

大于 3 减去 1 ，大于 5 减去 2 ，因为我选择了 2 个数字。

Greater than 3 is subtract by 1, and greater than 5 is subtract by 2 since I selected 2 numbers.

HTML

@foreach ($columns as $key => $column)
    <div class="checkbox checkbox-danger col-xs-6 el{{ $column->Field  }}">
        <input type="checkbox" name="CheckboxDelete[]" id="check{{ $column->Field  }}" data-column="{{ $key }}" value="{{ $column->Field }}">
        <label for="check{{ $column->Field  }}"><b style="color: grey">{{ strtoupper($column->Field) }}</b></label>
    </div>
@endforeach

这是我的代码，但仅在被删除1时才可用

Here is my code, but it's only when deleted 1, and not in a position as well.

$searchArr = array_search( $selectedDeletedNumbers, $items);
unset($items[$searchArr]);
$numbers = [];
foreach ($items as $item) {
    if ($item > $col[1])
        $numbers[] = $item - 1;  
}

谢谢。

推荐答案

为简洁起见，我将您的输入数据称为：

For clarity and brevity, I'll refer to your input data as:

$array = [0, 3, 10, 5, 6, 9, 2, 7, 1, 4, 8, 11];
$deletes = [3, 5];

我的两个摘要都不需要进行排序或准备。

There is no sorting or preparation required for either of my snippets.

以下两项的输出是：

array (
  0 => 0,
  1 => 8,
  2 => 4,
  3 => 7,
  4 => 2,
  5 => 5,
  6 => 1,
  7 => 3,
  8 => 6,
  9 => 9,
)

大多数基于函数的方法：（）

Mostly function based approach: (Demo)

foreach (array_diff($array, $deletes) as $value) {
    $result[] = array_reduce(
        $deletes,
        function ($carry, $item) use ($value) {
            return $carry - ($value > $item);  
        },
        $value
    );
}
var_export($result);

*注：（$ value> $ item）将被评估为 true 或 false ， true = 1 和 false = 0 。

*note: ($value > $item) will evaluated as true or false, when used in arithmetic, true = 1 and false = 0.

基于语言构造的方法：（）

Language construct based approach: (Demo)

foreach ($array as $value) {
    foreach ($deletes as $delete) {
        if ($value == $delete) {
            continue 2;            // goto next value in outer loop without pushing
        }
        if ($value > $delete) {
            --$value;              // decrement value
        }
    }
    $result[] = $value;            // push adjusted value into result array
}
var_export($result);

此代码段的优势是零个函数调用和最小的变量声明。

The advantage in this snippet is that there are zero function calls and minimal variables declared.

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