如何编写查询以从数据快照中提取单个更改?

本文介绍了如何编写查询以从数据快照中提取单个更改?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 限时删除！！ 我需要创建一个进程来从表中提取更改，其中每一行都是另一个表中一行的快照.现实世界中的问题涉及很多表和很多字段，但作为一个简单的例子，假设我有以下快照数据:I need to create a process that will extract the changes from a table where each row is a snapshot of a row in another table. The real-world problem involves many tables with many fields, but as a simple example, suppose that I have the following snapshot data:Sequence DateTaken ID Field1 Field2-------- ----------- ---- ------ ------ 1 '2011-01-01' 1 'Red' 2 2 '2011-01-01' 2 'Blue' 10 3 '2011-02-01' 1 'Green' 2 4 '2011-03-01' 1 'Green' 3 5 '2011-03-01' 2 'Purple' 2 6 '2011-04-01' 1 'Yellow' 2Sequence 和 DateTaken 字段直接与快照表本身相关.ID 字段是源表的主键，Field1 和 Field2 是同一个(源)表中的其他字段.The Sequence and DateTaken fields relate directly to the snapshot table itself. The ID field is the primary key of the source table and Field1 and Field2 are other fields in the same (source) table.我可以通过这样的查询获得部分解决方案:I can get part-way to a solution with a query like this:WITH Snapshots (Sequence, DateTaken, ID, Field1, Field2, _Index)AS( SELECT Sequence, DateTaken, ID, Field1, Field2, ROW_NUMBER() OVER (ORDER BY ID, Sequence) _Index FROM #Snapshots)SELECT c.DateTaken, c.ID , c.Field1 Field1_Current, p.Field1 Field1_Previous, CASE WHEN c.Field1 = p.Field1 THEN 0 ELSE 1 END Field1_Changed , c.Field2 Field2_Current, p.Field2 Field2_Previous, CASE WHEN c.Field2 = p.Field2 THEN 0 ELSE 1 END Field2_ChangedFROM Snapshots cJOIN Snapshots p ON p.ID = c.ID AND (p._Index + 1) = c._IndexORDER BY c.Sequence DESC上面的查询将识别从一个快照到下一个快照的变化，但它仍然不是我需要的形式.输出中的每一行都可能包含多项更改.在一天结束时，我需要每次更改一行以标识更改的字段及其先前/当前值.实际未更改的字段需要从最终输出中排除.所以如果上面的查询输出是这样的:The above query will identify what is changing from one snapshot to the next, but it is still not in the form that I need. Each row in the output may contain several changes. At the end of the day, I need one row per change that identifies what field was changed, along with its previous/current values. Fields that have not actually changed will need to be excluded from the final output. So if the above query output is like this:DateTaken ID Field1_Current Field1_Previous Field1_Changed Field2_Current Field2_Previous Field2_Changed---------- -- -------------- --------------- -------------- -------------- --------------- --------------2011-04-01 1 Yellow Green 1 2 3 12011-02-01 1 Green Red 1 2 2 0我需要把它转换成这样:I need to transform that into something like this:DateTaken ID Field Previous Current---------- -- ------- -------- ---------2011-04-01 1 Field1 Green Yellow2011-04-01 1 Field2 3 22011-02-01 1 Field1 Red Green我以为我可以通过 UNPIVOT 到达那里，但我一直没能做到.我认为任何涉及游标或类似方法的解决方案都绝对是最后的手段.I thought I might be able to get there with UNPIVOT, but I've not been able to make that work. I consider any solution involving cursors or similar to be an absolute last resort.非常感谢您的建议.推荐答案这是一个使用 UNPIVOT 的工作示例.它基于我对我的问题的回答 更好的方法来部分取消透视SQL 中的对Here's a working sample that uses UNPIVOT. It's based on my answer to my question Better way to Partially UNPIVOT in Pairs in SQL这有一些不错的功能.添加其他字段很容易.只需将值添加到 SELECT 和 UNPIVOT 子句.您不必添加额外的 UNION 子句Adding additional fields is easy. Just add values to the SELECT and UNPIVOT clause. You don't have to add additional UNION clauseswhere 子句 WHERE curr.value 无论添加了多少字段，prev.value 都不会改变.The where clause WHERE curr.value <> prev.value never changes regardless of how many fields are added.性能出奇地快.如果您需要，它可以移植到当前版本的 OracleIts portable to Current versions of Oracle if you need thatSQLDeclare @Snapshots as table(Sequence int,DateTaken datetime,[id] int,field1 varchar(20),field2 int)INSERT INTO @Snapshots VALUES (1, '2011-01-01', 1, 'Red', 2), (2, '2011-01-01', 2, 'Blue', 10), (3, '2011-02-01', 1, 'Green', 2), (4, '2011-03-01', 1, 'Green' , 3), (5, '2011-03-01', 2, 'Purple', 2), (6, '2011-04-01', 1, 'Yellow', 2);WITH Snapshots (Sequence, DateTaken, ID, Field1, Field2, _Index)AS( SELECT Sequence, DateTaken, ID, Field1, Field2, ROW_NUMBER() OVER (ORDER BY ID, Sequence) _Index FROM @Snapshots), data as(SELECT c._Index , c.DateTaken , c.ID , cast(c.Field1 as varchar(max)) Field1 , cast(p.Field1 as varchar(max))Field1_Previous , cast(c.Field2 as varchar(max))Field2 , cast(p.Field2 as varchar(max)) Field2_PreviousFROM Snapshots cJOIN Snapshots p ON p.ID = c.ID AND (p._Index + 1) = c._Index), fieldsToRows AS (SELECT DateTaken, id, _Index, value, field FROM data p UNPIVOT (value FOR field IN (field1, field1_previous, field2, field2_previous) ) AS unpvt )SELECT curr.DateTaken, curr.ID, curr.field, prev.value previous, curr.value 'current'FROM fieldsToRows curr INNER JOIN fieldsToRows prev ON curr.ID = prev.id AND curr._Index = prev._Index AND curr.field + '_Previous' = prev.fieldWHERE curr.value <> prev.value输出DateTaken ID field previous current----------------------- ----------- --------- -------- -------2011-02-01 00:00:00.000 1 Field1 Red Green2011-03-01 00:00:00.000 1 Field2 2 32011-04-01 00:00:00.000 1 Field1 Green Yellow2011-04-01 00:00:00.000 1 Field2 3 22011-03-01 00:00:00.000 2 Field1 Blue Purple2011-03-01 00:00:00.000 2 Field2 10 2 这篇关于如何编写查询以从数据快照中提取单个更改?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 1403页，肝出来的..