问题描述
以下是我的数据集示例:
Here is an example of my dataset:
Dput -
(已删除)
我按照这个代码按月分组这个数据框:
And I am subsetting this data frame by month using this code:
simpleindoor.mean <- simple_trapindoors %>% group_by(month) %>% summarise(n=n(),mean = mean(bitingrate), stderror = std(bitingrate))
其中产生如下表格:
|Month| n | mean| stderror|
|-----|---|-------|---------|
|May | 12| 0.25| 0.13|
|June | 21| 0.53| 0.12|
|July | 21| 0.53| 0.12|
我想做的是在同一功能中计算每个月内个人FAMILY_ID的数量,并将其添加为simpleindoor.mean的新列。
What I would like to do is calculate the number of individual FAMILY_ID's within each month in the same function, and add it as a new column to "simpleindoor.mean".
FAMILY_ID是一个字符向量。例如 6001-032。因此,如果在5月份有12个独特的FAMILY_ID,则新的数据列将在匹配May的行中显示12个。
FAMILY_ID is a character vector. E.g."6001-032". So if there were 12 unique FAMILY_ID's in May, the new column of data would show 12 in the row matching "May".
我已经看到了一些例子,您可以在其中查找字符向量的特定实例,但是我很难找到一个例子,您可以在其中计算出在特定组。我如何做?
I have seen examples where you look for specific instances of a character vector, but I struggled to find an example where you can count the instances of unique character vectors occurring within a particular group. How do I do this?
谢谢。
推荐答案
你需要 n_distinct
simple_trapindoors %>% group_by(month) %>% summarise(n=n(),mean = mean(bitingrate), stderror = std(bitingrate),
UniqueFamilies = n_distinct(FAMILY_ID))
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