问题描述
如何在我不知道深度和每个深度的字段的递归方式中将嵌套的jsonb递归展平? (请参见下面的示例)
How can I recursively flatten a nested jsonb in postgres which I don't know the depth and the field at each depth? (see example below)
使用postgressql查询进行展平会很容易
A postgressql query to do the flattening would be much apreciated
{
"xx": "",
"xx": "",
"form": "xxx",
"type": "",
"content_type": "xxx",
"reported_date": ,
"contact": {
"imported_date": "",
"name": "",
"phone": "",
"alternate_phone": "",
"specialization": "",
"type": "",
"reported_date": ,
"parent": {
"_id": "xxx",
"_rev": "xxx",
"parent": "",
"type": "xxx"
}
}
}
我已经在堆栈溢出中进行了搜索,但是他们只考虑具有单个深度的jsonb,并且之前已经知道密钥了
I have searched in stack overflow but they only consider jsonb's which have a single depth and the keys are already known before
推荐答案
示例设置:
create table my_table(id int, data jsonb);
insert into my_table values
(1,
$${
"type": "a type",
"form": "a form",
"contact": {
"name": "a name",
"phone": "123-456-78",
"type": "contact type",
"parent": {
"id": "444",
"type": "parent type"
}
}
}$$);
递归查询对在任何级别上找到的每个json对象执行jsonb_each()
.新的密钥名称包含从根开始的完整路径:
The recursive query executes jsonb_each()
for every json object found on any level. New key names contain full path from the root:
with recursive flat (id, key, value) as (
select id, key, value
from my_table,
jsonb_each(data)
union
select f.id, concat(f.key, '.', j.key), j.value
from flat f,
jsonb_each(f.value) j
where jsonb_typeof(f.value) = 'object'
)
select id, jsonb_pretty(jsonb_object_agg(key, value)) as data
from flat
where jsonb_typeof(value) <> 'object'
group by id;
id | data
----+------------------------------------------
1 | { +
| "form": "a form", +
| "type": "a type", +
| "contact.name": "a name", +
| "contact.type": "contact type", +
| "contact.phone": "123-456-78", +
| "contact.parent.id": "444", +
| "contact.parent.type": "parent type"+
| }
(1 row)
如果您想获得此数据的平面视图,则可以使用此答案中所述的函数create_jsonb_flat_view()
平坦的聚合键/来自JSONB字段的值对吗?
If you want to get a flat view of this data you can use the function create_jsonb_flat_view()
described in this answer Flatten aggregated key/value pairs from a JSONB field?
您需要使用扁平化的jsonb创建一个表(或视图):
You need to create a table (or view) with flattened jsonb:
create table my_table_flat as
-- create view my_table_flat as
with recursive flat (id, key, value) as (
-- etc as above
-- but without jsonb_pretty()
现在您可以在表格上使用该功能了:
Now you can use the function on the table:
select create_jsonb_flat_view('my_table_flat', 'id', 'data');
select * from my_table_flat_view;
id | contact.name | contact.parent.id | contact.parent.type | contact.phone | contact.type | form | type
----+--------------+-------------------+---------------------+---------------+--------------+--------+--------
1 | a name | 444 | parent type | 123-456-78 | contact type | a form | a type
(1 row)
该解决方案在Postgres 9.5+中有效,因为它使用了此版本中引入的jsonb函数.如果您的服务器版本较旧,则强烈建议无论如何都要升级Postgres以便有效地使用jsonb.
The solution works in Postgres 9.5+, as it uses jsonb function introduced in this version. If your server version is older it is highly recommended to upgrade Postgres anyway to use jsonb efficiently.
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