问题描述
$ ./runtests.py -v tests/managers/test_customer.py:CustomerManagerTest.test_register_without_subscription --ipdb
...
test_register_without_subscription (tests.managers.test_customer.CustomerManagerTest) ...
- TRACEBACK --------------------------------------------------------------------
Traceback (most recent call last):
File "/usr/lib/python2.7/unittest/case.py", line 331, in run
testMethod()
File "*****/tests/managers/test_customer.py", line 198, in test_register_without_subscription
1/0
ZeroDivisionError: integer division or modulo by zero
--------------------------------------------------------------------------------
> *****/tests/managers/test_customer.py(198)test_register_without_subscription()
197 def test_register_without_subscription(self):
--> 198 1/0
199 ...
ipdb> import sys
ipdb> sys.exc_info()
(<type 'exceptions.AttributeError'>, AttributeError("Pdb instance has no attribute 'do_sys'",), <traceback object at 0x47eb908>)
ipdb>
我在 ipdb help
I could not find any command in ipdb help
that shows me current exception.
执行 import sys;打印sys.exc_info()
不起作用。
当前,我正在这样做:
try:
do_something_that_raises_an_exception()
except Exception as exc:
import ipdb; ipdb.set_trace()
然后我可以使用 exc
进行分析。
then I can work with exc
to analyze it.
如何轻松获得对当前有效例外的引用?
How to easily get a reference to the currently effective exception?
推荐答案
这也让我感到沮丧。我最终找到了答案,以及详细的说明。
This has frustrated me too for a while. I eventually found the answer here, along with a good detailed explanation.
简短的答案是,使用!
魔术前缀(!sys.exc_info()
):
The short answer is, use the !
magic prefix (!sys.exc_info()
):
In [4]: 1/0
---------------------------------------------------------------------------
ZeroDivisionError Traceback (most recent call last)
...
ipdb> !sys.exc_info()
(<type 'exceptions.AttributeError'>, AttributeError("'exceptions.ZeroDivisionError' object has no attribute '_render_traceback_'",), <traceback object at 0x101c55fc8>)
这基本上告诉调试器:不必猜测。这是我输入的python代码,从而阻止它试图猜测 sys的含义,在此过程中会引发一些内部异常,从而覆盖 sys.exc_info()
,保留您原来的例外。
This basically tells the debugger: "guessing wouldn't be necessary. it is python code I'm typing", thus preventing it from trying to guess what you mean by "sys", a process during which some internal exception is raised, overwriting sys.exc_info()
, which used to hold your original exception.
这篇关于获取当前异常的参考的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!