创建适用于intellisense的javascript函数

问题描述

我想利用visual studio intellisense，因此我读过：

I want to take advantage of visual studio intellisense therefore I have read:

无论如何为什么我没有得到intellisense：

Anyways why I do not get intellisense with:

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

function Test() {
    /// <returns type="Customer"></returns>

    var c = new Object();
    $.ajax({
        async: false,
        dataType: "json",
        url: "Ajax/GetCustomer.aspx",
        success: function (foundCustomer) {
            // I know that found customer is of type Customer
            c = foundCustomer;
        }
    });

    return c;
}

var x = Test();
x. // No intellicense! why?

我如何告诉visual studio知道该函数将返回TYPE <$ c的对象$ C>客户？例如，如果我替换函数Test for： function Test（）{return new Customer（）; } 然后intellicense将工作。

How can I tell visual studio know that the function is going to return an object of TYPE Customer? For example if I replace the function Test for: function Test(){ return new Customer(); } then intellicense will work.

我最终的目标是拥有类似于：

My Goal at the end is to have something like:

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

Object.prototype.CastToCustomer = function(){
    /// <returns type="Customer"></returns>
    return this;
}

$.ajax({
    async: false,
    dataType: "json",
    url: "Ajax/GetCustomer.aspx",
    success: function (foundCustomer) {

        foundCustomer = foundCustomer.CastToCustomer();
        foundCustomer.// Intellicense does not work :(
    }
});

我得到了很多json对象，我想使用这个辅助函数来强制转换它们。

I get a lot of json objects and I will like to cast them using this helper functions.

这是我最终做了什么：

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

$.ajax({
    async: false,
    dataType: "json",
    url: "Ajax/GetCustomer.aspx",
    success: function (foundCustomer) {
        // this will never be true on real browser. It is always true in visual studio (visual studio will now think that found customer is of type Customer ;)
        if (document.URL.length == 0) foundCustomer = new Customer();

        foundCustomer.// Intellisense works!!!!
    }
});

推荐答案

您正在将返回值初始化为对象所以这是Intellisense所基于的。如果您将其初始化为空客户，那么Intellisense将检测到它返回客户

You are initializing the return value to an Object so it's on that which the Intellisense is based. If you initialize it to an empty Customer, then the Intellisense will detect that it is returning a Customer

function Test() {

    var c = new Customer(); //only for Intellisense

    $.ajax({...});

    return c;
}

Test(). //Customer members now appear

---

您也可以使用 ///< param /> 指定参数类型：

$.ajax({
    ...

        success: function (foundCustomer) {
           /// <param name='foundCustomer' type='Customer' />
           foundCustomer. //Customer members appear            
        }
});

---

最后，您的文件.URL.length 技巧也可用于强制转换方法：

---

Finally, your document.URL.length trick can also be used in the casting method:

Object.prototype.CastToCustomer = function() {

  var c = new Customer();
  if (document.URL.length) c = this;
  return c;

}

这篇关于创建适用于intellisense的javascript函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！