静态数组初始化

有什么想法吗？如果是m_ptr不是一个指针数组我会初始化它 像这样：classA * classB :: m_ptr = 0;" 现在阵列怎么样？Hello,I really don''t understand the simplest thing at the moment. I have a staticarray of pointers to a class . How do we initialize it?class classA{public:int x1;};class classB{public:void foo() { cout<< m_ptr[0]->x1; }static classA* m_ptr[4];};classA* classB::m_ptr[0]=0; // This is not correct !!!classA* classB::m_ptr[1]=0; // This is not correct !!!classA* classB::m_ptr[2]=0; // This is not correct !!!classA* classB::m_ptr[3]=0; // This is not correct !!!int main(){classB* ptr = new classB;ptr->foo();return 0;}Any idea? If "m_ptr" was not an array of pointers I would had initialize itlike this: "classA* classB::m_ptr=0;"What about arrays now?推荐答案 " Makis Papapanagiotou" <硒******************** @ siemens.com>在消息中写道 news：bj ********** @ news.mch.sbs.de ..."Makis Papapanagiotou" <Se********************@siemens.com> wrote in messagenews:bj**********@news.mch.sbs.de...你好， 指向类的静态指针数组。我们如何初始化它？ 班级A {公共： int x1; }; 班级classB {公开： void foo（）{cout<< m_ptr [0] - > X 1; } static classA * m_ptr [4]; }; classA * classB :: m_ptr [0] = 0; //这不正确!!! classA * classB :: m_ptr [1] = 0; //这不正确!!! classA * classB :: m_ptr [2] = 0; //这不正确!!! classA * classB :: m_ptr [3] = 0; //这不正确!!! int main（） {classB * ptr = new classB; ptr-> foo （）; 返回0; } 任何想法？如果是m_ptr这不是一个指针数组我会像这样初始化：classA * classB :: m_ptr = 0;" 现在阵列怎么样？ Hello, I really don''t understand the simplest thing at the moment. I have astatic array of pointers to a class . How do we initialize it? class classA { public: int x1; }; class classB { public: void foo() { cout<< m_ptr[0]->x1; } static classA* m_ptr[4]; }; classA* classB::m_ptr[0]=0; // This is not correct !!! classA* classB::m_ptr[1]=0; // This is not correct !!! classA* classB::m_ptr[2]=0; // This is not correct !!! classA* classB::m_ptr[3]=0; // This is not correct !!! int main() { classB* ptr = new classB; ptr->foo(); return 0; } Any idea? If "m_ptr" was not an array of pointers I would had initializeit like this: "classA* classB::m_ptr=0;" What about arrays now? 初始化任何数组的方式相同 classA * classB :: m_ptr [4] = {0,0,0,0}; 但由于零初始化是默认值，因此您根本不需要初始化 。 classA * classB： ：m_ptr [4]; johnSame way you initialise any arrayclassA* classB::m_ptr[4] = { 0, 0, 0, 0 };but since zero initialisation is the default, you don''t need to initialiseit at all.classA* classB::m_ptr[4];john " Makis Papapanagiotou" <硒******************** @ siemens.com>在消息中写道 news：bj ********** @ news.mch.sbs.de ..."Makis Papapanagiotou" <Se********************@siemens.com> wrote in messagenews:bj**********@news.mch.sbs.de...你好， 指向类的静态指针数组。我们如何初始化它？ 班级A {公共： int x1; }; 班级classB {公开： void foo（）{cout<< m_ptr [0] - > X 1; } static classA * m_ptr [4]; }; classA * classB :: m_ptr [0] = 0; //这不正确!!! classA * classB :: m_ptr [1] = 0; //这不正确!!! classA * classB :: m_ptr [2] = 0; //这不正确!!! classA * classB :: m_ptr [3] = 0; //这不正确!!! Hello, I really don''t understand the simplest thing at the moment. I have astatic array of pointers to a class . How do we initialize it? class classA { public: int x1; }; class classB { public: void foo() { cout<< m_ptr[0]->x1; } static classA* m_ptr[4]; }; classA* classB::m_ptr[0]=0; // This is not correct !!! classA* classB::m_ptr[1]=0; // This is not correct !!! classA* classB::m_ptr[2]=0; // This is not correct !!! classA* classB::m_ptr[3]=0; // This is not correct !!! 试试这个 - classA * classB :: m_ptr [] = {0};Try this -classA* classB::m_ptr[]={0}; 这篇关于静态数组初始化的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！