本文介绍了具有模板类参数的模板类专业化的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 29岁程序员,3月因学历无情被辞! 说我有:template < typename T >class ClassA{ void doTheStuff (T const * t);};template < typename T >class ClassB{ // Some stuff...};我想专门为 ClassB 模板的所有实例使用 doTheStuff 方法,如下所示:I'd like to specialize the doTheStuff method for all instances of the ClassB template like this:template <typename T>void ClassA< ClassB< T > >::doTheStuff (ClassB< T > const * t){ // Stuff done in the same way for all ClassB< T > classes}当然,这行不通.遗憾的是我不知道我怎么能做到这一点.But of course, this doesn't work. Shame is I don't know how I could do that.使用 Visual Studio 的编译器,我得到:With visual studio's compiler I get: error C2244: 'ClassA<T>::doTheStuff' : unable to match function definition to an existing declaration see declaration of 'ClassA<T>::doTheStuff' definition 'void ClassA<ClassB<T>>::doTheStuff(const ClassB<T> *)' existing declarations 'void ClassA<T>::doTheStuff(const T *)'我找到了这篇文章:模板类专业化,其中模板参数是一个模板所以我按照建议尝试了完整的类专业化,但它也不起作用:So I tried the full class specialization as advised but it doesn't work either:template <>template < typename U >class ClassA< ClassB< U > >{public: void doTheStuff (ClassB< U > const * b) { // Stuff done in the same way for all ClassB< T > classes }};视觉说:error C2910: 'ClassA<ClassB<U>>' : cannot be explicitly specialized欢迎任何帮助!浮出水面.推荐答案删除多余的 template 就可以了.Remove the extra template<> and it will work. 这篇关于具有模板类参数的模板类专业化的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 上岸,阿里云!