本文介绍了如何使用OpenNLP在R中获取POS标签?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这是R代码:

library(NLP) 
library(openNLP)
tagPOS <-  function(x, ...) {
s <- as.String(x)
word_token_annotator <- Maxent_Word_Token_Annotator()
a2 <- Annotation(1L, "sentence", 1L, nchar(s))
a2 <- annotate(s, word_token_annotator, a2)
a3 <- annotate(s, Maxent_POS_Tag_Annotator(), a2)
a3w <- a3[a3$type == "word"]
POStags <- unlist(lapply(a3w$features, `[[`, "POS"))
POStagged <- paste(sprintf("%s/%s", s[a3w], POStags), collapse = " ")
list(POStagged = POStagged, POStags = POStags)}
str <- "this is a the first sentence."
tagged_str <-  tagPOS(str)

输出为:

现在我只想从上面的句子中提取NN词,即句子,并将其存储到变量中.任何人都可以帮我解决这个问题.

Now I want to extract only NN word i.e sentence from the above sentence and want to store it into a variable .Can anyone help me out with this .

推荐答案

也许会有更优雅的方法来获得结果,但是这种方法应该可以工作:

There might be more elegant ways to obtain the result, but this one should work:

q <- strsplit(unlist(tagged_str[1]),'/NN')
q <- tail(strsplit(unlist(q[1])," ")[[1]],1)
#> q
#[1] "sentence"

希望这会有所帮助.

这篇关于如何使用OpenNLP在R中获取POS标签?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-29 07:43