问题描述
我有一个<UserListComponent />
,它输出一个<Contact />
组件和<Contacts />
表示的联系人列表.
I have a <UserListComponent />
which outputs one <Contact />
component and list of contacts presentated by <Contacts />
.
问题在于,在尝试安装<UserListComponent />
的测试中,测试输出错误Invariant Violation: You should not use <Route> or withRouter() outside a <Router>
The problem is that in the test for <UserListComponent />
when I try to mount it, test outputs an error Invariant Violation: You should not use <Route> or withRouter() outside a <Router>
withRouter()
用于<Contacts />
组件.
在父组件测试中如何在没有路由器的情况下模拟ContactsComponent
?
How can I mock ContactsComponent
without router in test of parent component?
我发现了一些类似的问题 https://www.bountysource.com/issues/49297944-invariant-violation-you-should-not-use-route-or-withrouter-outside-a-router 但是它仅描述组件被withRouter()
本身而不是子对象覆盖的情况.
I found some similar issue https://www.bountysource.com/issues/49297944-invariant-violation-you-should-not-use-route-or-withrouter-outside-a-routerbut it only describes situation when component is cover by withRouter()
itself, not children.
UserList.test.jsx
const mockResp = {
count: 2,
items: [
{
_id: 1,
name: 'User1',
email: '[email protected]',
phone: '+123456',
online: false
},
{
_id: 2,
name: 'User2',
email: '[email protected]',
phone: '+789123',
online: false
},
{
_id: 3,
name: 'User3',
email: '[email protected]',
phone: '+258369147',
online: false
}
],
next: null
}
describe('UserList', () => {
beforeEach(() => {
fetch.resetMocks()
});
test('should output list of users', () => {
fetch.mockResponseOnce(JSON.stringify(mockResp));
const wrapper = mount(<UserListComponent user={mockResp.items[2]} />);
expect(wrapper.find('.contact_small')).to.have.length(3);
});
})
UserList.jsx
export class UserListComponent extends PureComponent {
render() {
const { users, error } = this.state;
return (
<React.Fragment>
<Contact
userName={this.props.user.name}
content={this.props.user.phone}
/>
{error ? <p>{error.message}</p> : <Contacts type="contactList" user={this.props.user} contacts={users} />}
</React.Fragment>
);
}
}
Contacts.jsx
class ContactsComponent extends Component {
constructor() {
super();
this.state = {
error: null,
};
}
render() {
return (
<React.Fragment>
<SectionTitle title="Contacts" />
<div className="contacts">
//contacts
</div>
</React.Fragment>
);
}
}
export const Contacts = withRouter(ContactsComponent);
推荐答案
要测试包含<Route>
和withRouter
的组件(使用Jest),您需要在测试中而不是组件中导入Router
To test a component (with Jest) that contains <Route>
and withRouter
you need to import Router in you test, not in your component
import { BrowserRouter as Router } from 'react-router-dom';
并像这样使用它
app = shallow(
<Router>
<App />
</Router>);
这篇关于笑话,酵素:不断违反:您不应该使用< Route>或在< Router>外部使用Router()的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!