本文介绍了PHP:将INSERT MySQLi转换为PDO的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是PDO编程的新手.根据我的问题,有人可以帮助我将MySQLi转换为PDO吗?下面是代码:
I'm new in PDO programming. Based on my question, can anyone help me to convert MySQLi to PDO? Below is the code:
<?php
require_once "config.php";
$photo_before = $_POST['photo_before'];
$report_id = $_GET["report_id"] ?? "";
$sql_query = "UPDATE report SET photo_before ='$photo_before', time_photo_before = NOW(), ot_start = '16:00:00' WHERE report_id = '$report_id'";
if(mysqli_query($conn,$sql_query))
{
echo "Data Save!";
}
else
{
echo "Error!! Not Saved".mysqli_error($conn);
}
?>
希望有人能帮助我.谢谢
Hope there's a kind people to help me. Thanks
推荐答案
您可以按以下方式使用PDO
:
You can use PDO
as this:
$dsn = "mysql:host=localhost;dbname=myDatabase;charset=utf8mb4";
$options = [
PDO::ATTR_EMULATE_PREPARES => false, // turn off emulation mode for "real" prepared statements
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION, //turn on errors in the form of exceptions
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC, //make the default fetch be an associative array
];
try {
$pdo = new PDO($dsn, "username", "password", $options);
} catch (Exception $e) {
error_log($e->getMessage());
exit();
}
和准备好的语句:
$stmt = $pdo->prepare("UPDATE report SET photo_before =?, time_photo_before = NOW(), ot_start = '16:00:00' WHERE report_id = ?");
$stmt->execute([$_POST['photo_before'],$_GET["report_id"] ?? ""]);
这篇关于PHP:将INSERT MySQLi转换为PDO的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!