周围路过的boost ::支持ASIO ::知识产权:: TCP ::插座

问题描述

好吧，这是我目前的code片断：

Alright, this is my current code snippet:

namespace bai = boost::asio::ip;
bai::tcp::socket tcp_connect(std::string hostname, std::string port) {
    try {
        boost::asio::io_service io_service;
        bai::tcp::resolver resolver(io_service);

        // we now try to get a list of endpoints to the server
        bai::tcp::resolver::query query(hostname, port);
        bai::tcp::resolver::iterator endpoint_iterator = resolver.resolve(query);
        bai::tcp::resolver::iterator end;

        // looking for a successful endpoint connection
        bai::tcp::socket socket(io_service);
        boost::system::error_code error = boost::asio::error::host_not_found;
        while (error && endpoint_iterator != end) {
            socket.close();
            socket.connect(*endpoint_iterator++ , error);
        }

        if (error) throw boost::system::system_error(error);

        return socket;
    } catch (std::exception &ex) {
        std::cout << "Exception: " << ex.what() << "\n";
    }
}

这应该返回一个的boost ::支持ASIO ::知识产权:: TCP ::插座连接到主机名上端口。但是我得到INCOM prehensible 的shitload psented $ P $的boost ::不可复制错误。但我的问题是，我应该怎么绕过这些插座呢？这有什么错呢？

Which should return a boost::asio::ip::tcp::socket connected to hostname on port. However I get presented with a shitload of incomprehensible boost::noncopyable errors. But my question is, how should I pass around these sockets then? What's wrong with this?

推荐答案

插座无法复制。使用的boost :: shared_ptr的＆LT;李白:: TCP ::插座＆GT; 来代替。如果你的可能的复制插座你有各种各样的，如果你结束了与两个有趣的问题插座实例重新presenting相同底层操作系统插座 - 所以它是有道理的复制（因此由返回值，按值传递）是不允许的。

socket can't be copied. Use a boost::shared_ptr<bai::tcp::socket> instead. If you could copy a socket you'd have all sorts of funny issues if you ended up with two socket instances representing the same underlying OS socket - so it makes sense that copying (and therefore return by value, pass by value) is not allowed.

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