问题描述
我使用以下扩展方法来获取子字符串的 NSRange 数组:
I am using the following extension method to get NSRange array of a substring:
extension String {
func nsRangesOfString(findStr:String) -> [NSRange] {
let ranges: [NSRange]
do {
// Create the regular expression.
let regex = try NSRegularExpression(pattern: findStr, options: [])
// Use the regular expression to get an array of NSTextCheckingResult.
// Use map to extract the range from each result.
ranges = regex.matches(in: self, options: [], range: NSMakeRange(0, self.characters.count)).map {$0.range}
}
catch {
// There was a problem creating the regular expression
ranges = []
}
return ranges
}
}
但是,我没有意识到为什么它有时不起作用.这里有两种类似的情况,一种有效,另一种无效:
However, I didn't realize why it doesn't work sometimes. Here are two similar cases, one works and the other doesn't:
那个有效:
自我(字符串):
"וצפן (קרי: יִצְפֹּ֣ן) לַ֭יְשָׁרִים תּוּשִׁיָּ֑ה מָֹּהמָֹּהמְָֹתכחֵֹתתלֹן
findStr:
"קרי:"
那个没有:
自我(字符串):
"לִ֭נְצֹר אָרְח֣וֹת מִשְׁפָּ֑ט וְדֶ֖רֶךְחסידוחסידו(קִידוחסידואסידו(קִידוחסידואקידוורידוותתתמִשְׁפָּ֑ט לִ֭נְצֹר אָרְח֣וֹת)
findStr:
"קרי:"
(不过,另一种稳定的方法是合适的答案.)
(An alternate steady method would be an appropriate answer though.)
推荐答案
NSRange
范围以 UTF-16 代码单元(其中是 NSString
内部使用的),因此长度必须是self.utf16.count
:
NSRange
ranges are specified in terms of UTF-16 code units (whichis what NSString
uses internally), therefore the length must beself.utf16.count
:
ranges = regex.matches(in: self, options: [],
range: NSRange(location: 0, length: self.utf16.count))
.map {$0.range}
对于您的第二个字符串,我们有
In the case of your second string we have
let s2 = "לִ֭נְצֹר אָרְח֣וֹת מִשְׁפָּ֑ט וְדֶ֖רֶךְ חסידו (קרי: חֲסִידָ֣יו) יִשְׁמֹֽר׃"
print(s2.characters.count) // 46
print(s2.utf16.count) // 74
这就是为什么在您的代码中找不到该模式的原因.
and that's why the pattern is not found with your code.
从 Swift 4 开始,您还可以为整个字符串计算 NSRange
Starting with Swift 4 you can compute a NSRange
for the entire string also as
NSRange(self.startIndex..., in: self)
这篇关于Swift 正则表达式不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!