问题描述
我试图找出如何使用java获取二进制文件中的特定字节。我已经对字节级操作进行了大量阅读,并让自己彻底混淆了。现在我可以遍历文件,如下面的代码所示,并告诉它停在我想要的字节。但我知道这是一种吝啬的方式,并且有一种正确的方式来做到这一点。
I am trying to figure out how to get to a specific byte in a binary file using java. I've done a ton of reading on byte level operations and have gotten myself thoroughly confused. Right now I can loop through a file, as in the code below, and tell it to stop at the byte I want. But I know that this is ham-fisted and there is a 'right' way to do this.
因此,例如,如果我有一个文件,并且我需要从off-set 000400返回该字节,我怎么能从FileInputStream中获取它?
So for example if I have a file and I need to return the byte from off-set 000400 how can I a get this from a FileInputStream?
public ByteLab() throws FileNotFoundException, IOException {
String s = "/Volumes/Staging/Imaging_Workflow/B.Needs_Metadata/M1126/M1126-0001.001";
File file = new File(s);
FileInputStream in = new FileInputStream(file);
int read;
int count = 0;
while((read = in.read()) != -1){
System.out.println(Integer.toHexString(count) + ": " + Integer.toHexString(read) + "\t");
count++;
}
}
谢谢
推荐答案
你需要。您可以通过方法。
You need RandomAccessFile
for the job. You can set the offset by the seek()
method.
RandomAccessFile raf = new RandomAccessFile(file, "r");
raf.seek(400); // Goes to 400th byte.
// ...
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