获取qlist大小作为结构大小C ++

问题描述

您好，我怎样才能获得像sizeof struct这样的自己列表的大小。我知道sizeof是如何工作的。

Hello, How can i get the size of my own list like sizeof struct. I know how sizeof works for example.

enum NETCDF_Type
	{
		NETCDF_NONE,      //!< unknown data foramt
		NETCDF_STRING,
		NETCDF_UCHAR,		//!< signed 1 byte integer
		NETCDF_CHAR,		//!< signed 1 byte integer
		NETCDF_SHORT, 	//!< signed 2 byte integer
		NETCDF_INT,		//!< signed 4 byte integer
		NETCDF_USHORT,	//!< unsigned 2-byte int
		NETCDF_UINT,		//!< unsigned 4-byte int
		NETCDF_FLOAT32,	//!< signed 4-byte int
		NETCDF_DOUBLE64,	//!< signed 8-byte int
		NETCDF_LONGLONG,
		NETCDF_ULONGLONG
	};

void getSize( const QList< NETCDF_Type > myList )
{
     for( int i = 0; i < myList.count(); i++ )
     {
          //do something
          //I need a size of which NETCDF_Type i am using.
          //Without sizeof();
     }
}

我尝试过：

What I have tried:

struct MyStruct
{
     char v1;
     char v2;
     char v3;
     short v4;
};

int mSize = sizeof( MyStruct ); mSize => 6;

struct MyStruct
{
     char v1;
     char v2;
     char v3;
     char v4;
     short v;
};


int mSize = sizeof( MyStruct ); mSize => 6;

推荐答案

Quote：

//我需要一个我正在使用的NETCDF_Type的大小。

//没有sizeof（）;

//I need a size of which NETCDF_Type i am using.
//Without sizeof();

我会为此编写一个方法，例如

I would write a method for that, e.g.

size_t getSize(NETCDF_Type typ);

方法实现由您直接决定，使用开关。

[/ update]

The method implementation is up to you, in a straightforward approach, use a switch.
[/update]

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