本文介绍了Python超类反射的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如果我有 Python 代码
class A():经过B类():经过C类(A,B):经过
而且我有 C
类,有没有办法遍历它的超类(A
和 B
)?类似伪代码的东西:
def magicGetSuperClasses(cls):返回 [o[0] for o in inspect.getclasstree([cls]) if type(o[0]) == type]
但这是实现目标的Pythonian"方式吗?
解决方案
C.__bases__
是一个超类的数组,所以你可以像这样实现你的假设函数:
def magicGetSuperClasses(cls):返回 cls.__bases__
但我想在大多数情况下直接引用 cls.__bases__
会更容易.
If I have Python code
class A():
pass
class B():
pass
class C(A, B):
pass
and I have class C
, is there a way to iterate through it's super classed (A
and B
)? Something like pseudocode:
>>> magicGetSuperClasses(C)
(<type 'A'>, <type 'B'>)
One solution seems to be inspect module and getclasstree
function.
def magicGetSuperClasses(cls):
return [o[0] for o in inspect.getclasstree([cls]) if type(o[0]) == type]
but is this a "Pythonian" way to achieve the goal?
解决方案
C.__bases__
is an array of the super classes, so you could implement your hypothetical function like so:
def magicGetSuperClasses(cls):
return cls.__bases__
But I imagine it would be easier to just reference cls.__bases__
directly in most cases.
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