如何在java中将两个一维数组放入一个二维数组？

本文介绍了如何在java中将两个一维数组放入一个二维数组？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 我正在尝试从两个一维数组X1 []和X2 []构建一个二维数组double X [] []。 输入如下： X1 X2 0 1 0 2 1 2 1 5 2 3 2 4 3 4 3 5 4 5 4 6 5 6 5 7 6 7 我想要的输出是： X 0 1 0 2 1 2 1 5 2 3 2 4 3 4 3 5 4 5 4 6 5 6 5 7 6 7 然而它引发了异常：java.lang.ArrayIndexOutOfBoundsException：2 我们将非常感谢您的想法，提示或示例。我想知道我做错了什么。 我的尝试： 这里有一段代码，显示了数组的实现和一些上下文： 以前 下面的代码 X1 []和X2 [已初始化 行 10 和行 11 分别为： double []度= new double [numNodes]; for （ int id = 0 ; id < numNodes; id ++）{ Vector neighbors =（Vector ）netInfo。 get （id）; 系统。 out .println（id + + neighbors + + neighbors.size（））; degree [id] = neighbors.size（）; } double X1 [ ] = new double [edgeList.size（）]; double X2 [] = new 双 [edgeList.size（）]; double Y [] = new 双 [edgeList.size（）]; // EBWC也是1-NOVER for （ int edgeIndex = 0 ; edgeIndex < edgeList.size（）; edgeIndex ++）{ String edge =（ String ）edgeList。 get （edgeIndex）; StringTokenizer stk = new StringTokenizer（edge）; int uID = Integer.parseInt（stk.nextToken（））; int vID = Integer.parseInt（stk.nextToken（））; X1 [edgeIndex] =度[uID]; X2 [edgeIndex] =度[vID]; 向量uNeighbors =（向量）netInfo。 get （uID） ; 向量vNeighbors =（向量）netInfo。 get （vID）; // 找到交叉点 Vector commonNeighbors = new Vector（）; for （ int uindex = 0 ; uindex < uNeighbors.size（）; uindex ++）{ int uNeighbID =（（整数）uNeighbors。 get （uindex））。的intValue（）; if （vNeighbors.contains（uNeighbID））{ commonNeighbors。 add （uNeighbID）; } // 检查uNeighbID是否在vNeighbors // 如果它在那里，将uNeighbID添加到commonNeighbors } // 查找联合 Vector AllNeighbors =（Vector）uNeighbors.clone（）; // Set< Integer> temp = new HashSet< Integer>（）; for （ int vindex = 0 ; vindex < vNeighbors.size（）; vindex ++）{ // temp.add（i）; int i =（（整数）vNeighbors。 get （vindex））。intValue（）; if （！AllNeighbors.contains（i）） AllNeighbors。 add （i）; } double NOVER = 0 ; if （AllNeighbors.size（）> 2 ） NOVER =（（ double ）commonNeighbors.size （））/（AllNeighbors.size（） - 2）; Y [edgeIndex] = 1 - NOVER; // 使用交集和联合，找到边缘uID-vID的EBWC分数为1-NOVER（uID，vID） // 放入uID vID和边界到EBMap的EBWC得分EBWC 系统。 out .println（edgeIndex + + X1 [edgeIndex] + + X2 [edgeIndex] + + Y [edgeIndex]）; } //使用X1 []和X2构造X [] []二维数组[/] double [] [] X = {X1，X2}; for（int rowIndex = 0; rowIndex< edgeList.size（）; rowIndex ++）{ for（int colIndex = 0; colIndex< 2（）; colIndex ++）{ System.out.print（X [rowIndex] [colIndex] +）; } System.out.println（）; } 解决方案 很难读取这样的非格式化代码！ 使用List / ArrayList来放置你的二维数组项，然后从中提供一个数组。 关注： java - 将2D数组转换为1D数组 - Stack Overflow [ ^ ] 如何在Java中将二维数组转换为一维数组 - Stack Overflow [ ^ ] 查看以下代码片段并根据您的要求： public class Main { public static void main（ String [] args）{ int [] x1 = { 1 ， 2 ， 3 }; int [] x2 = { 4 ， 5 ， 6 }; int [] [] x = new int [ 3 ] [ 2 ]; for （ int i = 0 ; i< x1.length; i ++）{x [i] [ 0 ] = x1 [i]; } for （ int i = 0 ; i< x2.length; i ++）{x [i] [ 1 ] = x2 [i] ; } for （ int i = 0 ; i < x.length; i ++）{ for （ int j = 0 ; j < x [i] .length; j ++）{ System。 out .print（x [i] [j ] + ）; } 系统。 out .println（）; } } } 该示例将转换两个1D数组： x1：1,2,3 x2：4,5,6 到2D阵列： x： 1 4 2 5 3 6 注意一些循环代码块可以变成一种更好地重复使用的方法。那是你要思考的问题。 I am trying to construct a two-dimensional array double X[][] from two one-dimensional arrays X1[] and X2[].Input is as follows:X1 X20 10 21 21 52 32 43 43 54 54 65 65 76 7And my desired output is:X0 10 21 21 52 32 43 43 54 54 65 65 76 7However it threw an exception: java.lang.ArrayIndexOutOfBoundsException: 2And ideas, hints, or examples would be greatly appreciated. I want to learn what I am doing wrong.What I have tried:Here is a snippet of code that shows the implementation of the arrays and some context:Previously in the code below is how X1[] and X2[] were initialized in line 10 and line 11 respectively: double[] degree = new double[numNodes]; for (int id = 0; id < numNodes; id++){ Vector neighbors = (Vector) netInfo.get(id); System.out.println(id+" "+neighbors+" "+neighbors.size() ); degree[id] = neighbors.size(); } double X1[] = new double[edgeList.size()]; double X2[] = new double[edgeList.size()]; double Y[] = new double[edgeList.size()]; //EBWC which is also 1-NOVER for (int edgeIndex = 0; edgeIndex < edgeList.size(); edgeIndex++){ String edge = (String) edgeList.get(edgeIndex); StringTokenizer stk = new StringTokenizer(edge); int uID = Integer.parseInt(stk.nextToken()); int vID = Integer.parseInt(stk.nextToken()); X1[edgeIndex] = degree[uID]; X2[edgeIndex] = degree[vID]; Vector uNeighbors = (Vector) netInfo.get(uID); Vector vNeighbors = (Vector) netInfo.get(vID); // finding the intersection Vector commonNeighbors = new Vector(); for (int uindex = 0; uindex < uNeighbors.size(); uindex++){ int uNeighbID = ( (Integer) uNeighbors.get(uindex) ).intValue(); if (vNeighbors.contains(uNeighbID)) { commonNeighbors.add(uNeighbID); } // check if uNeighbID is in vNeighbors // if it is there, add uNeighbID to commonNeighbors } // finding the union Vector AllNeighbors = (Vector) uNeighbors.clone(); //Set<Integer> temp=new HashSet<Integer>(); for(int vindex = 0; vindex < vNeighbors.size(); vindex++){ //temp.add(i); int i = ( (Integer) vNeighbors.get(vindex) ).intValue(); if (!AllNeighbors.contains(i)) AllNeighbors.add(i); } double NOVER = 0; if (AllNeighbors.size() > 2) NOVER = ( (double) commonNeighbors.size() )/ (AllNeighbors.size()-2); Y[edgeIndex] = 1 - NOVER; // using the intersection and union, find EBWC scores for the edge uID-vID as 1-NOVER(uID, vID) // put uID vID and the EBWC score for the edge to the TreeMap EBWC System.out.println(edgeIndex+" "+X1[edgeIndex]+" "+X2[edgeIndex]+" "+Y[edgeIndex]); }// construct the X[][] two-dim array using X1[] and X2[] double[][] X = {X1, X2}; for (int rowIndex = 0; rowIndex < edgeList.size(); rowIndex++){ for (int colIndex = 0; colIndex < 2(); colIndex++){ System.out.print(X[rowIndex][colIndex]+" "); } System.out.println(); } 解决方案 Its very hard to read such a non-formatted code!Use a List/ArrayList to put your 2-dimensional array items and then feed an array from it.Follow:java - Convert a 2D array into a 1D array - Stack Overflow[^]How can you convert a 2 dimensional array into a 1 dimensional array in Java - Stack Overflow[^]Check out the following code snippet and adapt to your requirement:public class Main { public static void main(String[] args) { int[] x1 = {1,2,3}; int[] x2 = {4,5,6}; int[][] x = new int[3][2]; for (int i=0;i<x1.length;i++){ x[i][0]=x1[i]; } for (int i=0;i<x2.length;i++){ x[i][1]=x2[i]; } for (int i = 0; i < x.length; i++) { for (int j = 0; j < x[i].length; j++) { System.out.print(x[i][j] + " "); } System.out.println(); } }}The example turns two 1D array:x1: 1,2,3x2: 4,5,6into a 2D array:x:1 42 53 6Notice some of the looping code blocks can be turned into a method for better re-use. That is for you to ponder. 这篇关于如何在java中将两个一维数组放入一个二维数组？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！