问题描述
我最近开始使用R，但我认为我不太了解hist()函数.我目前正在使用长度为296的数字矢量，我想将其分为10个相等的间隔，并生成频率直方图以查看哪些值落入每个间隔.我以为hist(dataset, breaks = 10)可以完成工作，但是它将其分为12个间隔.我显然误解了breaks的作用.
I've recently started using R and I don't think I'm understanding the hist() function well. I'm currently working with a numeric vector of length 296, and I'd like to divide it up into 10 equal intervals, and produce a frequency histogram to see which values fall into each interval. I thought hist(dataset, breaks = 10) would do the job, but it's dividing it into 12 intervals instead. I obviously misunderstood what breaks does.
如果我想在直方图中将数据分为10个间隔，该怎么做?谢谢.
If I want to divide up my data into 10 intervals in my histogram, how should I go about doing that? Thank you.
推荐答案
按照文档，如果您给breaks参数指定一个数字，则该参数将被视为建议，因为它会提供漂亮断点.如果要强制将其设置为10个等距的垃圾箱，最简单的方法可能是以下操作，
As per the documentation, if you give the breaks argument a single number, it is treated as a suggestion as it gives pretty breakpoints. If you want to force it to be 10 equally spaced bins, the easiest is probably the following,
x = rnorm(50)
hist(x, breaks = seq(min(x), max(x), length.out = 11))
长度应为n+1，其中n是所需箱的数量.
The length should be n+1 where n is the number of desired bins.
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