使用不同的键获取具有重复值的枚举变量的值

问题描述

 公开枚举卡
 {
 AceClubs = 11，
 AceDiamonds = 11，
 AceHearts = 11，
 AceSpades = 11，
 DeuceClubs = 2，
 DeuceDiamonds = 2，
 DeuceHearts = 2，
 DeuceSpades = 2，
 EightClubs = 8，
 EightDiamonds = 8，
 EightHearts = 8，
 EightSpades = 8，
 FiveClubs = 5，
 FiveDiamonds = 5，
 FiveHearts = 5，
 FiveSpades = 5，
 FourClubs = 4，
 FourDiamonds = 4，
 FourHearts = 4 ，
 FourSpades = 4，
 JackClubs = 11，
 JackDiamonds = 11，
 JackHearts = 11，
 JackSpades = 11，
 KingClubs = 13，
 KingDiamonds = 13，
 KingHearts = 13，
 KingSpades = 13，
 NineClubs = 9，
 NineDiamonds = 9，
 NineHearts = 9，
 NineSpades = 9，
 QueenClubs = 12，
 QueenDiamonds = 12，
 QueenHearts = 12，
 QueenSpades = 12 ，
 SevenClubs = 7，
 SevenDiamonds = 7，
 SevenHearts = 7，
 SevenSpades = 7，
 SixClubs = 6，
 SixDiamonds = 6，
 SixHearts = 6，
 SixSpades = 6，
 TenClubs = 10，
 TenDiamonds = 10，
 TenHearts = 10，
 TenSpades = 10，
 ThreeClubs = 3，
 ThreeDiamonds = 3，
 ThreeHearts = 3，
 ThreeSpades = 3 
} 
  

我想从枚举中创建一个列表

  var cards = Enum.GetValues （typeof运算（卡））; 
  

但它会在列表中返回重复的键。

解决方案

我建议使用两个 ：

  public enum CardSuit {
俱乐部= 1，
钻石= 2，
 Hearts = 3，
 Spades = 4，
}; 
 
 public enum CardValue {
 Ace = 1，
 Deuce = 2，
 ... 
 King = 13，
}; 
  

然后实现扩展方法以获取实际的卡值（因为 Jack 和 Ace 对应于 11 ）：

  public static class ValueExtensions（）{
 public static int ActualValue（此CardValue值）{
 if（value == CardValue.Ace）
 return 11; // Ace是11 
 else 
 return（int）value; 
} 
} 
  

最后

  public class Card {
 public Card（CardSuit suit，CardValue value）{
 Suit = suit; 
 Value = value; 
} 
 
 public CardSuit Suit {get; private set;} 
 public CardValue Value {get;私人设置;} 
} 
 
 ... 
 
卡[]包=枚举
 .GetValues（typeof（CardSuit））
 .OfType< CardSuit>（）
 .SelectMany（suit =>枚举
 .GetValues（typeof（CardValue））
 .OfType< CardValue>（）
 .Select => new Card（suit，value）））
 .ToArray（）; 
 
 // TODO：在这里卸载包
卡[] hand = pack.Take（5）.ToArray（）; 
 
 int handValue = hand.Sum（card => card.Value.ActualValue（））; 
  

I've an Enum for 52 playing cards, as mentioned below,

public enum Card
{
        AceClubs = 11,
        AceDiamonds = 11,
        AceHearts = 11,
        AceSpades = 11,
        DeuceClubs = 2,
        DeuceDiamonds = 2,
        DeuceHearts = 2,
        DeuceSpades = 2,
        EightClubs = 8,
        EightDiamonds = 8,
        EightHearts = 8,
        EightSpades = 8,
        FiveClubs = 5,
        FiveDiamonds = 5,
        FiveHearts = 5,
        FiveSpades = 5,
        FourClubs = 4,
        FourDiamonds = 4,
        FourHearts = 4,
        FourSpades = 4,
        JackClubs = 11,
        JackDiamonds = 11,
        JackHearts = 11,
        JackSpades = 11,
        KingClubs = 13,
        KingDiamonds = 13,
        KingHearts = 13,
        KingSpades = 13,
        NineClubs = 9,
        NineDiamonds = 9,
        NineHearts = 9,
        NineSpades = 9,
        QueenClubs = 12,
        QueenDiamonds = 12,
        QueenHearts = 12,
        QueenSpades = 12,
        SevenClubs = 7,
        SevenDiamonds = 7,
        SevenHearts = 7,
        SevenSpades = 7,
        SixClubs = 6,
        SixDiamonds = 6,
        SixHearts = 6,
        SixSpades = 6,
        TenClubs = 10,
        TenDiamonds = 10,
        TenHearts = 10,
        TenSpades = 10,
        ThreeClubs = 3,
        ThreeDiamonds = 3,
        ThreeHearts = 3,
        ThreeSpades = 3
  }

I want to create a list from enum

 var cards = Enum.GetValues(typeof(Card));

but it returns duplicate keys in list.

解决方案

I suggested using two enums for suit and value:

  public enum CardSuit {
    Clubs = 1,
    Diamonds = 2,
    Hearts = 3,
    Spades = 4,
  };

  public enum CardValue {
    Ace = 1,
    Deuce = 2, 
    ...
    King = 13,
  };

then implement an extension method to get actual card value (since both Jack and Ace corresponds to 11):

  public static class ValueExtensions() {
    public static int ActualValue(this CardValue value) { 
      if (value == CardValue.Ace)
        return 11; // Ace is 11
      else
        return (int) value;
    } 
  }

Finally

  public class Card {
    public Card (CardSuit suit, CardValue value) {
      Suit = suit;
      Value = value;  
    }

    public CardSuit Suit {get; private set;} 
    public CardValue Value {get; private set;} 
  }

  ...

  Card[] pack = Enum
    .GetValues(typeof(CardSuit))
    .OfType<CardSuit>()
    .SelectMany(suit => Enum
      .GetValues(typeof(CardValue))
      .OfType<CardValue>()
      .Select(value => new Card(suit, value)))
    .ToArray();

  //TODO: Shuffle the pack here
  Card[] hand = pack.Take(5).ToArray();

  int handValue = hand.Sum(card => card.Value.ActualValue()); 

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