本文介绍了爪哇算法做出直金字塔的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
___________1
__________1 2 1
_________1 2 3 2 1
________1 2 3 4 3 2 1
______1 2 3 4 5 4 3 2 1
_____1 2 3 4 4 4 4 4 3 2 1
___1 2 3 3 3 3 3 3 3 3 3 2 1
__1 2 2 2 2 2 2 2 2 2 2 2 2 2 1
_1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
我想使用Java这个金字塔?任何建议?
I would like to create this pyramid using java? Any suggestion?
推荐答案
这将surve的目的。您可以更改号码5至另一号码比5。如其他。 1,2,3,...,6,8
This will surve the purpose. You can change the number 5 to another number other than 5. eg. 1,2,3,.. , 6,8
public static void main(String[] args) {
List<String> list = new LinkedList<String>();
for(int i = 5; i > 0; i-- ){
wrapWithNumber(list, i);
}
for (String string : editListToBeInTriangleShape(list)) {
System.out.println(string);
};
}
/**
* Wrap the number strings in the llist with a perticular number.
* @param list list of Strings
* @param ba number which need to wrapp the list with.
*/
private void wrapWithNumber(List<String> list, final int ba) {
list.add(0, String.format("%d",ba));
for (int i = 1; i < list.size(); i++) {
String newformat = "%1$d " + list.get(i) + " %1$d";
list.remove(list.get(i));
list.add(i,String.format(newformat, ba));
}
String lastFormat = "%1$d";
for(int i = 0; i < 2 * list.size();i++){
lastFormat += " %1$d";
}
if(list.size() != 1) {
list.add(String.format(lastFormat, ba));
}
}
/**
* Arrage the Strings in the list in triangular manner.
* @param list list of Strings.
*/
private List<String> editListToBeInTriangleShape(final List<String> list) {
final List<String> returnList = new LinkedList<String>();
for (int i = list.size(); i > 0; i--) {
String s = list.get(list.size()-i);
int possition = list.size()*2 + s.length()/2;
returnList.add(String.format("%"+possition+"s", s));
}
return returnList;
}
放出来了这一点:
out put of this :
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 4 4 4 4 3 2 1
1 2 3 3 3 3 3 3 3 3 3 2 1
1 2 2 2 2 2 2 2 2 2 2 2 2 2 1
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
这篇关于爪哇算法做出直金字塔的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!