本文介绍了PHP警告:为foreach()提供了无效的参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

为什么会收到此PHP警告?

Why am I getting this PHP Warning?

这是我的代码:

// look for text file for this keyword
if (empty($site["textdirectory"])) {
    $site["textdirectory"] = "text";
}
if (file_exists(ROOT_DIR.$site["textdirectory"].'/'.urlencode($q).'.txt')) {
    $keywordtext =
     file_get_contents(ROOT_DIR.$site["textdirectory"].'/'.urlencode($q).'.txt');
}
else {
    $keywordtext = null;
}

$keywordsXML = getEbayKeywords($q);

foreach($keywordsXML->PopularSearchResult as $item) {
    $topicsString = $item->AlternativeSearches;
   $relatedString = $item->RelatedSearches;
   if (!empty($topicsString)) {
        $topics =  split(";",$topicsString);
    }
    if (!empty($relatedString)) {
        $related = split(";",$relatedString);
    }

}

$node = array();
$node['keywords'] = $q;

2

$xml = ebay_rss($node);

$ebayItems = array();
$totalItems = count($xml->channel->item);

$totalPages = $totalItems / $pageSize;


$i = 0;
foreach  ($xml->channel->item as $item) {
  $ebayRss =
    $item->children('http://www.ebay.com/marketplace/search/v1/services');

    if ($i>=($pageSize*($page-1)) && $i<($pageSize*$page)) {
        $newItem = array();
        $newItem['title'] = $item->title;
        $newItem['link'] = buyLink($item->link, $q);
        $newItem['image'] = ebay_stripImage($item->description);
        $newItem['currentbid'] = ebay_convertPrice($item->description);
        $newItem['bidcount'] = $ebayRss->BidCount;
        $newItem['endtime'] = ebay_convertTime($ebayRss->ListingEndTime);
        $newItem['type'] = $ebayRss->ListingType;
        if (!empty($ebayRss->BuyItNowPrice)) {
            $newItem['bin'] = ebay_convertPrice($item->description);
        }
        array_push($ebayItems, $newItem);
    }
    $i++;
}


$pageNumbers = array();
for ($i=1; $i<=$totalPages; $i++) {
    array_push($pageNumbers, $i);
}

3

// get user guides
$guidesXML = getEbayGuides($q);
$guides = array();
foreach ($guidesXML->guide as $guideXML) {
    $guide = array();
    $guide['url'] = makeguideLink($guideXML->url, $q);
    $guide['title'] = $guideXML->title;
    $guide['desc'] = $guideXML->desc;
    array_push($guides,$guide);
}

是什么原因导致此警告?

What causes this warning?

推荐答案

您应该使用 is_array 函数

You should check that what you are passing to foreach is an array by using the is_array function

如果您不确定它将是一个数组,则可以始终使用以下PHP示例代码进行检查:

If you are not sure it's going to be an array you can always check using the following PHP example code:

if (is_array($variable)) {

  foreach ($variable as $item) {
   //do something
  }
}

这篇关于PHP警告:为foreach()提供了无效的参数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-26 11:32
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