本文介绍了PHP警告:为foreach()提供了无效的参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
为什么会收到此PHP警告?
Why am I getting this PHP Warning?
这是我的代码:
// look for text file for this keyword
if (empty($site["textdirectory"])) {
$site["textdirectory"] = "text";
}
if (file_exists(ROOT_DIR.$site["textdirectory"].'/'.urlencode($q).'.txt')) {
$keywordtext =
file_get_contents(ROOT_DIR.$site["textdirectory"].'/'.urlencode($q).'.txt');
}
else {
$keywordtext = null;
}
$keywordsXML = getEbayKeywords($q);
foreach($keywordsXML->PopularSearchResult as $item) {
$topicsString = $item->AlternativeSearches;
$relatedString = $item->RelatedSearches;
if (!empty($topicsString)) {
$topics = split(";",$topicsString);
}
if (!empty($relatedString)) {
$related = split(";",$relatedString);
}
}
$node = array();
$node['keywords'] = $q;
2
$xml = ebay_rss($node);
$ebayItems = array();
$totalItems = count($xml->channel->item);
$totalPages = $totalItems / $pageSize;
$i = 0;
foreach ($xml->channel->item as $item) {
$ebayRss =
$item->children('http://www.ebay.com/marketplace/search/v1/services');
if ($i>=($pageSize*($page-1)) && $i<($pageSize*$page)) {
$newItem = array();
$newItem['title'] = $item->title;
$newItem['link'] = buyLink($item->link, $q);
$newItem['image'] = ebay_stripImage($item->description);
$newItem['currentbid'] = ebay_convertPrice($item->description);
$newItem['bidcount'] = $ebayRss->BidCount;
$newItem['endtime'] = ebay_convertTime($ebayRss->ListingEndTime);
$newItem['type'] = $ebayRss->ListingType;
if (!empty($ebayRss->BuyItNowPrice)) {
$newItem['bin'] = ebay_convertPrice($item->description);
}
array_push($ebayItems, $newItem);
}
$i++;
}
$pageNumbers = array();
for ($i=1; $i<=$totalPages; $i++) {
array_push($pageNumbers, $i);
}
3
// get user guides
$guidesXML = getEbayGuides($q);
$guides = array();
foreach ($guidesXML->guide as $guideXML) {
$guide = array();
$guide['url'] = makeguideLink($guideXML->url, $q);
$guide['title'] = $guideXML->title;
$guide['desc'] = $guideXML->desc;
array_push($guides,$guide);
}
是什么原因导致此警告?
What causes this warning?
推荐答案
您应该使用 is_array 函数
You should check that what you are passing to foreach
is an array by using the is_array function
如果您不确定它将是一个数组,则可以始终使用以下PHP示例代码进行检查:
If you are not sure it's going to be an array you can always check using the following PHP example code:
if (is_array($variable)) {
foreach ($variable as $item) {
//do something
}
}
这篇关于PHP警告:为foreach()提供了无效的参数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!