从代码中得到分段错误如何摆脱它？

问题描述

当我尝试调试此程序时，它显示程序接收信号SIGSEGV，Segmentation fault。我不知道该怎么做才是我发布这个问题的原因。


我尝试了什么：

When I tried to debug this program it shows Program received signal SIGSEGV,Segmentation fault. I don't know what to do that's why I posted this question.

What I have tried:

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
static int count=0;
struct node
{
	int coef;
	int pow;
	struct node *link;
};

struct node *head=NULL;

void showoff()
{
	struct node *t1;
	t1=head;
	while(t1!=NULL)
	{
		printf("|%d|%d|%x|--",t1->coef,t1->pow,t1->link);
		t1=t1->link;
	}
}

int main()
{
	int n,i=0;
	struct node *temp,*t;
	t=head;
	printf("Number of nodes\n");
	scanf("%d",&n);
	
	while(i<n)
	{
		temp=(struct node*)malloc(sizeof(struct node));
		temp->coef=NULL;
		temp->pow=NULL;
		
		if(count==0)
		{
			temp->link=head;
			head=temp;
		}
		if(count==1)
		{
			temp->link=head->link;
			head->link=temp;
		}
		if(count>1)
		{
			while(t->link!=NULL)    /*Responsible for error. Can you explain why*/
			{
				t=t->link;
			}
			temp->link=t->link;
			t->link=temp;
		}
		count++;
		i++;
	}
	showoff();
}

推荐答案

// ...
	for( i = 0; i < n; ++i )    // I prefer a for loop for this
	{
		// ... logic goes here

		printf( "i is %d, count is %d\n", i, count );
		showoff();
		count++;
	}

struct node *temp,*t;

制作：

Make it:

struct node *temp;
struct node *t;

试试吧重建并运行看看会发生什么。

我想知道结构*是否未被正确声明。

Just try that and rebuild and run see what happens.
I'm wondering if the struct * isn't being declared properly.

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