OSError: [Errno 9] python 3 中的文件描述符错误

问题描述

我是一名初级/中级程序员，目前正在尝试用 Python 3 编写一个简单的 Web 服务器.但是，每当我运行该模块时，我都会收到 OSError: [Errno 9] Bad file descriptor.我已经在互联网上搜索了答案，但我似乎无法自己解决这个问题.这是代码和回溯:

I'm a beginning/intermediate level programmer currently trying to write a simple web server in Python 3. However, whenever I run the module I get OSError: [Errno 9] Bad file descriptor. I've scoured the internet looking for answers, but I can't seem to figure this one out on my own. Here is the code and traceback:

#import socket module

from socket import *

serverSocket=socket(AF_INET,SOCK_STREAM)

#Prepare a server socket

serverSocket.bind(('IP address', 8000))
serverSocket.listen(1)

while True:
#Establish the connection

 print('Ready to serve...')

 (connectionSocket, addr) = serverSocket.accept()

 print ('connected from',addr)

 try:


      message=connectionSocket.recv(1024)
      filename=message.split()[1]
      print (filename)

      filename=message.split()[1]

      f=open(filename[1:])

      outputdata=f.read()

 #Send one HTTP header line into socket

      connectionSocket.send('HTTP/1.1 200 OK')

 #Send the content of the requested file to the client

      for i in range(0, len(outputdata)):
           connectionSocket.send(outputdata[i])
           connectionSocket.close()
 except IOError as err:
      print ('IO error')


           #Send response message for file not found

      connectionSocket.send(b'file not found')

                #Close client socket
      connectionSocket.close()
      serverSocket.close()

追溯:

Traceback (most recent call last):
  File "/Users/BigRed/Desktop/SOS/webServer.py", line 17, in <module>
    (connectionSocket, addr) = serverSocket.accept()
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/socket.py", line       184, in accept
fd, addr = self._accept()
OSError: [Errno 9] Bad file descriptor

推荐答案

当出现 OIError 时，您正在调用 serverSocket.close().但是当你重新进入 while 循环时，你调用 serverSocket.accept() 而没有调用 serverSocket=socket(AF_INET,SOCK_STREAM)，这失败了，因为你已经调用了 close()

When there is a OIError, you're calling serverSocket.close(). But when you re-enter in the while loop, you call serverSocket.accept() without call serverSocket=socket(AF_INET,SOCK_STREAM), and this fails, because you've called the close()

请参阅此帖子

希望有所帮助

PD: Django 开发人员不经常使用套接字.=)

PD: django developers don't use socket regularly. =)

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