本文介绍了检查命令是否在某些通道中运行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我目前将其作为命令:
bot.on('message', function (message) {
if (message.content == '!register') {
message.member.send("Registered!");
let memberRole = message.member.guild.roles.find("name", "Verified");
message.member.addRole(memberRole);
}
});
我想要它,因此此命令只能在称为注册的文本通道中运行(如果需要,我具有通道ID).
I want it so this command can only be ran in a text channel called registration (I have the channel id if needed).
推荐答案
如果只有一个称为 registration
的文本通道,则为以下代码:
Here is the code if you only have one textchannel called registration
:
bot.on('message', function (message) {
if (message.content == '!register' && message.channel.name.toLowerCase() === 'registration') {
message.member.send("Registered!");
let memberRole = message.member.guild.roles.find("name", "Verified");
message.member.addRole(memberRole);
}
});
如果您有两个称为 registration
的文本通道,我将检查该通道的ID.可以使用以下代码完成此操作:
If you have two textchannels called registration
, I would check the ID of the channel. This can be done with this code:
bot.on('message', function (message) {
if (message.content == '!register' && message.channel.id === 'YOUR CHANNEL ID') {
message.member.send("Registered!");
let memberRole = message.member.guild.roles.find("name", "Verified");
message.member.addRole(memberRole);
}
});
顺便说一句,您不必使用 message.member
来接收行会对象.您可以简单地执行 message.guild
!
By the way, you don't have to use message.member
to receive the guild object. You can simply do message.guild
!
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