数组索引的PHP对象键值比较

问题描述

我有两个数组，两个数组的索引都包含对象

I have two arrays where indexes of both arrays are contains objects

$array1=array(1) {
[0]=> object(stdClass) (3) {
    ["aid"]=> string(1) "1"
    ["a_number"]=> string(1) "0"
    ["id_of"]=> string(1) "1"
    }
}


$array2=array(3) {
[0]=> object(stdClass) (3) {
    ["id"]=> string(1) "1",
    ["number"]=> string(1) "0" ,
    ["flag"]=> string(1) "1" ,
    ["zflag"]=> string(1) "0" ,
    ["xflag"]=> string(1) "1"
    } ,
    [1]=> object(stdClass) (3) {
    ["id"]=> string(1) "2",
    ["number"]=> string(1) "2" ,
    ["flag"]=> string(1) "2" ,
    ["zflag"]=> string(1) "0" ,
    ["xflag"]=> string(1) "1"
    },
    [1]=> object(stdClass) (3) {
    ["id"]=> string(1) "3",
    ["number"]=> string(1) "3",
    ["flag"]=> string(1) "3" ,
    ["zflag"]=> string(1) "0" ,
    ["xflag"]=> string(1) "1"
    }
}

我想比较$array2所有元素中$id键的值和$id_of每个$array1元素的值，如果不存在，则返回$array1元素.以下是我的代码，但不起作用

I want to compare between the value of $id key in all elements of $array2 with the value of $id_of each element of $array1, if it's not exist then return the element of $array1. Below is my code but it doesn't work

public function unanswered($array1,$array2){
        if(!(empty($array2))){
            $unanswered_arrays=array();
            foreach($array1 as $b){
                foreach($array2 as $a){
                    if($b->id != $a->id_of){
                        array_push($unanswered_arrays,(object)$b);
                    }
                }
            }
            return $unanswered_arrays;
        }
        return $array1;
    }

推荐答案

如果您将函数用作unanswered($array1,$array2)，则在foreach循环中将$array1替换为$array2，反之亦然，或者通过unanswered($array2,$array1)而不是.

If you're using your function as unanswered($array1,$array2) then replace $array1 with $array2 and vice versa in foreach loops or pass unanswered($array2,$array1) instead of.

演示

Demo

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