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问题描述
我有一个List<MyObject>
...MyObject有一个称为 LineId (整数)...
I have a List<MyObject>
...MyObject has a propert called LineId (integer)...
因此,我需要在列表中分隔所有连续的LineId ...
So, I need separate all consecutive LineId in List ...
示例:
List<MyObject> :
LineId =1
LineId =1
LineId =1
LineId =2
LineId =1
LineId =2
结果必须为4个分隔的列表:
The result must be 4 separeted lists:
LineId =1
LineId =1
LineId =1
-------------
LineId =2
-------------
LineId =1
-------------
LineId =2
因此,我必须分隔所有连续的LineId ...
So, I must separate all consecutive LineId ...
有没有一种简单的方法可以使用Linq做到这一点?
Is there an easy way to do that using Linq?
谢谢
推荐答案
这看起来很丑,但想法很明确,我认为它可行:
This looks ugly but the idea is clear and I think it works:
var agg = list.Aggregate(
new List<List<Line>>(),
(groupedLines, line) => {
if (!groupedLines.Any()) {
groupedLines.Add(new List<Line>() { line });
}
else {
List<Line> last = groupedLines.Last();
if (last.First().LineId == line.LineId) {
last.Add(line);
}
else {
List<Line> newGroup = new List<Line>();
newGroup.Add(line);
groupedLines.Add(newGroup);
}
}
return groupedLines;
}
);
这里我假设您有:
class Line { public int LineId { get; set; } }
和
List<Line> list = new List<Line>() {
new Line { LineId = 1 },
new Line { LineId = 1 },
new Line { LineId = 1 },
new Line { LineId = 2 },
new Line { LineId = 1 },
new Line { LineId = 2 }
};
现在,如果我执行
foreach(var lineGroup in agg) {
Console.WriteLine(
"Found {0} consecutive lines with LineId = {1}",
lineGroup.Count,
lineGroup.First().LineId
);
foreach(var line in lineGroup) {
Console.WriteLine("LineId = {0}", line.LineId);
}
}
我知道了
Found 3 consecutive lines with LineId = 1
LineId = 1
LineId = 1
LineId = 1
Found 1 consecutive lines with LineId = 2
LineId = 2
Found 1 consecutive lines with LineId = 1
LineId = 1
Found 1 consecutive lines with LineId = 2
LineId = 2
打印在控制台上.
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